Folding a linked list using a Stack - java

Here is my program to fold a linked list using a Stack:
public Node middle(Node head) {
Node slow = head;
Node fast = head;
while (fast != null && fast.next != null) {
fast = fast.next.next;
slow = slow.next;
}
return slow;
}
public Node foldList(Node head){
Node mid = middle(head);
Node f = mid.next;
Stack<Node> stacks = new Stack<>();
if (head == null) return head;
while (f != null){
stacks.push(f);
f = f.next;
}
Node temp = head;
Node forv = head.next;
while(!stacks.isEmpty()) {
temp.next = stacks.pop();
temp = temp.next;
temp.next = forv;
temp = temp.next;
forv = forv.next;
}
return head;
}
Here is the code of the middle() and foldList() methods. When I run it it gets stuck in an infinite loop. Can anybody help me find out why this is happening?

The problem is that you are doing this:
linked list: 1-2-3-4-5-6
Put second half in a Stack:
linked list: 1-2-3-4-5-6
stack: 5-6
Insert the stack nodes between the linked list nodes:
linked list: 1-6-2-3-4-5-6-2-3-4-5-6-2-3-4-5-6.....infinite
You need to remove the second half of the nodes (the ones put on the stack) from the linked list before you start folding.
Since it's a linked list, you can simply nullify mid.next:
public Node foldList(Node head){
Node mid = middle(head);
Node f = mid.next;
// remove the second half
mid.next = null
Stack<Node> stacks = new Stack<>();
if (head == null) return head;
while (f != null){
stacks.push(f);
f = f.next;
}
Here's my full code, using Deque instead of Stack (because Stack is old and moldy):
import java.util.ArrayDeque;
import java.util.Deque;
public class LinkedListFolder {
public static void main(String[] args) {
Node head = createLinkedList();
foldList(head);
print(head);
}
private static Node createLinkedList() {
Node head = new Node(1);
Node current = head;
for (int i = 2; i < 7; i++) {
current.next = new Node(i);
current = current.next;
}
return head;
}
private static void print(Node node) {
System.out.println(node);
while (node.next != null) {
node = node.next;
System.out.println(node);
}
}
public static void foldList(Node head) {
if (head == null) {
return;
}
Deque<Node> nodesToFold = getNodesToFold(head);
Node current = head;
Node successor = head.next;
while (!nodesToFold.isEmpty()) {
current.next = nodesToFold.pop();
current = current.next;
current.next = successor;
current = current.next;
successor = successor.next;
}
}
private static Deque<Node> getNodesToFold(Node head) {
Node middle = findMiddle(head);
Node current = middle.next;
middle.next = null;
Deque<Node> nodesToFold = new ArrayDeque<>();
while (current != null) {
nodesToFold.push(current);
current = current.next;
}
return nodesToFold;
}
public static Node findMiddle(Node head) {
Node slow = head;
Node fast = head;
while (fast != null && fast.next != null) {
fast = fast.next.next;
slow = slow.next;
}
return slow;
}
static class Node {
public int value;
public Node next;
public Node(int value) {
this.value = value;
}
#Override
public String toString() {
return String.format("Node{value=%d}", value);
}
}
}
Output:
Node{value=1}
Node{value=6}
Node{value=2}
Node{value=5}
Node{value=3}
Node{value=4}

Related

Stack overflow - Merge sort on LinkedList

I'm trying to perform merge sort on a LinkedList(Manually implemented and not using the collections one) 🔗. Not sure why I'm getting stack overflow error ⚠. Seeking help, thank you in advance 🙂.
public class LinkedList3 {
public static class Node {
int data;
Node next;
public Node(int data) {
this.data = data;
this.next = null;
}
}
public static Node head;
public static Node tail;
public void addFirst(int data) {
Node newNode = new Node(data);
if(head == null) {
head = tail = newNode;
return;
}
newNode.next = head;
head = newNode;
}
public void addLast(int data) {
Node newNode = new Node(data);
if(head == null) {
head = tail = newNode;
return;
}
tail.next = newNode;
tail = newNode;
}
public void print() {
Node temp = head;
while(temp != null) {
System.out.print(temp.data + " -> ");
temp = temp.next;
}
System.out.println("null");
}
private Node getMid(Node head) {
Node slow = head;
Node fast = head;
while(fast != null && fast.next != null) {
slow = slow.next;
fast = fast.next.next;
}
return slow;
}
private Node merge(Node head1, Node head2) {
Node mergedLL = new Node(-1);
Node temp = mergedLL;
while(head1 != null && head2 != null) {
if(head1.data <= head2.data) {
temp.next = head1;
head1 = head1.next;
temp = temp.next;
} else {
temp.next = head2;
head2 = head2.next;
temp = temp.next;
}
}
while(head1 != null) {
temp.next = head1;
head1 = head1.next;
temp = temp.next;
}
while(head2 != null) {
temp.next = head2;
head2 = head2.next;
temp = temp.next;
}
return mergedLL.next;
}
public Node mergeSort(Node head) {
if(head == null || head.next == null) {
return head;
}
Node mid = getMid(head);
Node rightHead = mid.next;
mid.next = null;
Node newLeft = mergeSort(head);
Node newRight = mergeSort(rightHead);
return merge(newLeft, newRight);
}
public static void main(String args[]) {
LinkedList3 ll = new LinkedList3();
ll.addFirst(1);
ll.addFirst(2);
ll.addFirst(3);
ll.addFirst(4);
ll.addFirst(5);
ll.print();
ll.head = ll.mergeSort(ll.head);
ll.print();
}
}
I assume that I might be missing/error/typo something in the mergeSort method. I've checked the code multiple times but getting the same error. I couldn't find a solution or a reason for overflow in this linked list.
5 -> 4 -> 3 -> 2 -> 1 -> null
Exception in thread "main" java.lang.StackOverflowError
at LinkedList3.getMid(LinkedList3.java:54)
at LinkedList3.mergeSort(LinkedList3.java:100)
at LinkedList3.mergeSort(LinkedList3.java:105)
at LinkedList3.mergeSort(LinkedList3.java:105)
at LinkedList3.mergeSort(LinkedList3.java:105)
at LinkedList3.mergeSort(LinkedList3.java:105)
at LinkedList3.mergeSort(LinkedList3.java:105)

Reverse singly linked list

I have the below program to reverse elements in a singly linked list. I can't get it to work. I have used simple swapping of variables technique to swap the nodes but when I print, it doesn't go beyond the first node.
public static void reverseLinkedList(Node head) {
Node current = head;
Node temp = null;
while (current != null && current.next != null) {
temp = current;
current = current.next;
current.next = temp;
}
}
public static void printData(Node head) {
Node currentNode = head;
while (true) {
System.out.println(currentNode.data);
if (currentNode.next != null) {
currentNode = currentNode.next;
} else {
break;
}
}
}
I prefer to return the head node after the function. Keeps thing simple
Node reverse(Node node)
{
Node prev = null;
Node current = node;
Node next = null;
while (current != null) {
next = current.next;
current.next = prev;
prev = current;
current = next;
}
node = prev;
return node;
}
Alternatively you can opt for the simpler recursive version
Node reverse(Node head) {
if(head == null) {
return head;
}
if(head.next == null) {
return head;
}
Node newHeadNode = reverse(head.next);
head.next.next = head;
head.next = null;
return newHeadNode;
}
You are assigning the next of the current variable to itself which is wrong. You can do like below.
public void reverseLL(Node head) {
Node currentNode = head, prevLink = null, nextNode = null;
while (currentNode != null) {
nextNode = currentNode.next;
currentNode.next = prevLink;
prevLink = currentNode;
currentNode = nextNode;
}
head = prevLink;
}
In your algorithm the first two nodes of the list creates a loop after the first iteration of the while loop.It's better to use the below algorithm.
public static void reverseLinkedList(Node head) {
Node current = head;
Node prev = head;
Node next = head.next;
while (current != null && current.next != null) {
current=next;
next=current.next;
current.next=prev;
prev=current;
}
head=current;
}

Trying to figure out size of a linked list null pointer error

For the below code, I would like to know why the size of the linked list keeps giving me a null pointer exeption and why my pushEnd method to push a new node at the end doesnt work, it add an element after a few nodes and gets rid of rest.
class Node {
int data;
Node next;
Node(int data){
this.data = data;
}
}
public class LinkedList {
Node head;
/* Inserts a new Node at front of the list. */
public Node push(int data)
{
Node newNode = new Node(data);
newNode.next = head;
return head = newNode;
}
public Node pushEnd(int data) {
Node newNode = new Node(data);
if (head == null) {
head = newNode;
}
newNode.next = null;
while(head != null) {
head = head.next;
head.next = newNode;
return newNode;
}
return head;
}
public int getSize() {
int size = 0;
while(this.head != null) {
size++;
head = head.next;
}
return size;
}
public void printList() {
while (this.head !=null) {
System.out.print(head.data + "-->");
head = head.next;
}
System.out.println(head);
}
}
public class Tester {
public static void main(String[] args) {
LinkedList ll = new LinkedList();
ll.push(35);
ll.push(100);
ll.push(14);
ll.push(44);
ll.push(10);
ll.push(8);
System.out.println("Created Linked list is:");
ll.printList();
System.out.println(ll.getSize());
}
}
I want to figure out the size of the linked list and be able to add nodes at the end.
Your while loops modify the head variable directly. This causes your other code to fail because now head is pointing to the last node in the list.
Create a new local variable for use in the while loops (instead of modifying head directly). That should fix it!
You are changing head reference, due to which you are getting incorrect output. You should make temp refer to head, do your operation using temp which will not affect head. It should be like below:
public class LinkedList {
Node head;
/* Inserts a new Node at front of the list. */
public void push(int data) {
Node newNode = new Node(data);
newNode.next = head;
head = newNode;
}
public void pushEnd(int data) {
Node newNode = new Node(data);
if (head == null) {
head = newNode;
return;
}
newNode.next = null;
Node temp = head;
while (temp.next != null) {
temp = temp.next;
}
temp.next = newNode;
}
public int getSize() {
int size = 0;
Node temp = head;
while (temp != null) {
size++;
temp = temp.next;
}
return size;
}
public void printList() {
Node temp = this.head;
while (temp != null) {
System.out.print(temp.data + "-->");
temp = temp.next;
}
System.out.println(temp);
}
}
class Node {
int data;
Node next;
Node(int data) {
this.data = data;
}
}

Reverse Singly Linked List Java [duplicate]

This question already has answers here:
How to reverse a singly-linked list in blocks of some given size in O(n) time in place?
(4 answers)
Closed 4 years ago.
Can someone tell me why my code dosent work? I want to reverse a single linked list in java: This is the method (that doesnt work correctly)
public void reverseList(){
Node before = null;
Node tmp = head;
Node next = tmp.next;
while(tmp != null){
if(next == null)
return;
tmp.next = before;
before = tmp;
tmp = next;
next = next.next;
}
}
And this is the Node class:
public class Node{
public int data;
public Node next;
public Node(int data, Node next){
this.data = data;
this.next = next;
}
}
On input 4->3->2->1 I got output 4. I debugged it and it sets pointers correctly but still I dont get why it outputs only 4.
Node next = tmp.next;
while(tmp != null){
So what happens when tmp == null?
You almost got it, though.
Node before = null;
Node tmp = head;
while (tmp != null) {
Node next = tmp.next;
tmp.next = before;
before = tmp;
tmp = next;
}
head = before;
Or in nicer (?) naming:
Node reversedPart = null;
Node current = head;
while (current != null) {
Node next = current.next;
current.next = reversedPart;
reversedPart = current;
current = next;
}
head = reversedPart;
ASCII art:
<__<__<__ __ : reversedPart : head
(__)__ __ __
head : current: > > >
public Node<E> reverseList(Node<E> node) {
if (node == null || node.next == null) {
return node;
}
Node<E> currentNode = node;
Node<E> previousNode = null;
Node<E> nextNode = null;
while (currentNode != null) {
nextNode = currentNode.next;
currentNode.next = previousNode;
previousNode = currentNode;
currentNode = nextNode;
}
return previousNode;
}
The method for reversing a linked list is as below;
Reverse Method
public void reverseList() {
Node<E> curr = head;
Node<E> pre = null;
Node<E> incoming = null;
while(curr != null) {
incoming = curr.next; // store incoming item
curr.next = pre; // swap nodes
pre = curr; // increment also pre
curr = incoming; // increment current
}
head = pre; // pre is the latest item where
// curr is null
}
Three references are needed to reverse a list: pre, curr, incoming
... pre curr incoming
... --> (n-1) --> (n) --> (n+1) --> ...
To reverse a node, you have to store previous element, so that you can use the simple stament;
curr.next = pre;
To reverse the current element's direction. However, to iterate over the list, you have to store incoming element before the execution of the statement above because as reversing the current element's next reference, you don't know the incoming element anymore, that's why a third reference needed.
The demo code is as below;
LinkedList Sample Class
public class LinkedList<E> {
protected Node<E> head;
public LinkedList() {
head = null;
}
public LinkedList(E[] list) {
this();
addAll(list);
}
public void addAll(E[] list) {
for(int i = 0; i < list.length; i++)
add(list[i]);
}
public void add(E e) {
if(head == null)
head = new Node<E>(e);
else {
Node<E> temp = head;
while(temp.next != null)
temp = temp.next;
temp.next = new Node<E>(e);
}
}
public void reverseList() {
Node<E> curr = head;
Node<E> pre = null;
Node<E> incoming = null;
while(curr != null) {
incoming = curr.next; // store incoming item
curr.next = pre; // swap nodes
pre = curr; // increment also pre
curr = incoming; // increment current
}
head = pre; // pre is the latest item where
// curr is null
}
public void printList() {
Node<E> temp = head;
System.out.print("List: ");
while(temp != null) {
System.out.print(temp + " ");
temp = temp.next;
}
System.out.println();
}
public static class Node<E> {
protected E e;
protected Node<E> next;
public Node(E e) {
this.e = e;
this.next = null;
}
#Override
public String toString() {
return e.toString();
}
}
}
Test Code
public class ReverseLinkedList {
public static void main(String[] args) {
Integer[] list = { 4, 3, 2, 1 };
LinkedList<Integer> linkedList = new LinkedList<Integer>(list);
linkedList.printList();
linkedList.reverseList();
linkedList.printList();
}
}
Output
List: 4 3 2 1
List: 1 2 3 4
If this isn't homework and you are doing this "manually" on purpose, then I would recommend using
Collections.reverse(list);
Collections.reverse() returns void, and your list is reversed after the call.
We can have three nodes previous,current and next.
public void reverseLinkedlist()
{
/*
* Have three nodes i.e previousNode,currentNode and nextNode
When currentNode is starting node, then previousNode will be null
Assign currentNode.next to previousNode to reverse the link.
In each iteration move currentNode and previousNode by 1 node.
*/
Node previousNode = null;
Node currentNode = head;
while (currentNode != null)
{
Node nextNode = currentNode.next;
currentNode.next = previousNode;
previousNode = currentNode;
currentNode = nextNode;
}
head = previousNode;
}
public void reverse() {
Node prev = null; Node current = head; Node next = current.next;
while(current.next != null) {
current.next = prev;
prev = current;
current = next;
next = current.next;
}
current.next = prev;
head = current;
}
// Java program for reversing the linked list
class LinkedList {
static Node head;
static class Node {
int data;
Node next;
Node(int d) {
data = d;
next = null;
}
}
// Function to reverse the linked list
Node reverse(Node node) {
Node prev = null;
Node current = node;
Node next = null;
while (current != null) {
next = current.next;
current.next = prev;
prev = current;
current = next;
}
node = prev;
return node;
}
// prints content of double linked list
void printList(Node node) {
while (node != null) {
System.out.print(node.data + " ");
node = node.next;
}
}
public static void main(String[] args) {
LinkedList list = new LinkedList();
list.head = new Node(85);
list.head.next = new Node(15);
list.head.next.next = new Node(4);
list.head.next.next.next = new Node(20);
System.out.println("Given Linked list");
list.printList(head);
head = list.reverse(head);
System.out.println("");
System.out.println("Reversed linked list ");
list.printList(head);
}
}
OUTPUT: -
Given Linked list
85 15 4 20
Reversed linked list
20 4 15 85
I know the recursive solution is not the optimal one, but just wanted to add one here:
public class LinkedListDemo {
static class Node {
int val;
Node next;
public Node(int val, Node next) {
this.val = val;
this.next = next;
}
#Override
public String toString() {
return "" + val;
}
}
public static void main(String[] args) {
Node n = new Node(1, new Node(2, new Node(3, new Node(20, null))));
display(n);
n = reverse(n);
display(n);
}
static Node reverse(Node n) {
Node tail = n;
while (tail.next != null) {
tail = tail.next;
}
reverseHelper(n);
return (tail);
}
static Node reverseHelper(Node n) {
if (n.next != null) {
Node reverse = reverseHelper(n.next);
reverse.next = n;
n.next = null;
return (n);
}
return (n);
}
static void display(Node n) {
for (; n != null; n = n.next) {
System.out.println(n);
}
}
}
I don't get it... why not doing this :
private LinkedList reverseLinkedList(LinkedList originalList){
LinkedList reversedList = new LinkedList<>();
for(int i=0 ; i<originalList.size() ; i++){
reversedList.add(0, originalList.get(i));
}
return reversedList;
}
I find this easier.
A more elegant solution would be to use recursion
void ReverseList(ListNode current, ListNode previous) {
if(current.Next != null)
{
ReverseList(current.Next, current);
ListNode temp = current.Next;
temp.Next = current;
current.Next = previous;
}
}
I tried the below code and it works fine:
Node head = firstNode;
Node current = head;
while(current != null && current.next != null){
Node temp = current.next;
current.next = temp.next;
temp.next = head;
head = temp;
}
Basically one by one it sets the next pointer of one node to its next to next node, so from next onwards all nodes are attached at the back of the list.
Node reverse_rec(Node start) {
if (start == null || start -> next == null) {
return start;
}
Node new_start = reverse(start->next);
start->next->next = start;
start->next = null;
return new_start;
}
Node reverse(Node start) {
Node cur = start;
Node bef = null;
while (cur != null) {
Node nex = cur.next;
cur.next = bef;
bef = cur;
cur = nex;
}
return bef;
}
I think your problem is that your initially last element next attribute isn't being changed becuase of your condition
if(next == null)
return;
Is at the beginning of your loop.
I would move it right after tmp.next has been assigned:
while(tmp != null){
tmp.next = before;
if(next == null)
return;
before = tmp;
tmp = next;
next = next.next;
}
Use this.
if (current== null || current.next==null) return current;
Node nextItem = current.next;
current.next = null;
Node reverseRest = reverse(nextItem);
nextItem.next = current;
return reverseRest
or Java Program to reverse a Singly Linked List
package com.three;
public class Link {
int a;
Link Next;
public Link(int i){
a=i;
}
}
public class LinkList {
Link First = null;
public void insertFirst(int a){
Link objLink = new Link(a);
objLink.Next=First;
First = objLink;
}
public void displayLink(){
Link current = First;
while(current!=null){
System.out.println(current.a);
current = current.Next;
}
}
public void ReverseLink(){
Link current = First;
Link Previous = null;
Link temp = null;
while(current!=null){
if(current==First)
temp = current.Next;
else
temp=current.Next;
if(temp==null){
First = current;
//return;
}
current.Next=Previous;
Previous=current;
//System.out.println(Previous);
current = temp;
}
}
public static void main(String args[]){
LinkList objLinkList = new LinkList();
objLinkList.insertFirst(1);
objLinkList.insertFirst(2);
objLinkList.insertFirst(3);
objLinkList.insertFirst(4);
objLinkList.insertFirst(5);
objLinkList.insertFirst(6);
objLinkList.insertFirst(7);
objLinkList.insertFirst(8);
objLinkList.displayLink();
System.out.println("-----------------------------");
objLinkList.ReverseLink();
objLinkList.displayLink();
}
}
You can also try this
LinkedListNode pointer = head;
LinkedListNode prev = null, curr = null;
/* Pointer variable loops through the LL */
while(pointer != null)
{
/* Proceed the pointer variable. Before that, store the current pointer. */
curr = pointer; //
pointer = pointer.next;
/* Reverse the link */
curr.next = prev;
/* Current becomes previous for the next iteration */
prev = curr;
}
System.out.println(prev.printForward());
package LinkedList;
import java.util.LinkedList;
public class LinkedListNode {
private int value;
private LinkedListNode next = null;
public LinkedListNode(int i) {
this.value = i;
}
public LinkedListNode addNode(int i) {
this.next = new LinkedListNode(i);
return next;
}
public LinkedListNode getNext() {
return next;
}
#Override
public String toString() {
String restElement = value+"->";
LinkedListNode newNext = getNext();
while(newNext != null)
{restElement = restElement + newNext.value + "->";
newNext = newNext.getNext();}
restElement = restElement +newNext;
return restElement;
}
public static void main(String[] args) {
LinkedListNode headnode = new LinkedListNode(1);
headnode.addNode(2).addNode(3).addNode(4).addNode(5).addNode(6);
System.out.println(headnode);
headnode = reverse(null,headnode,headnode.getNext());
System.out.println(headnode);
}
private static LinkedListNode reverse(LinkedListNode prev, LinkedListNode current, LinkedListNode next) {
current.setNext(prev);
if(next == null)
return current;
return reverse(current,next,next.getNext());
}
private void setNext(LinkedListNode prev) {
this.next = prev;
}
}
public class ReverseLinkedList {
public static void main(String args[]){
LinkedList<String> linkedList = new LinkedList<String>();
linkedList.add("a");
linkedList.add("b");
linkedList.add("c");
linkedList.add("d");
linkedList.add("e");
linkedList.add("f");
System.out.println("Original linkedList:");
for(int i = 0; i <=linkedList.size()-1; i++){
System.out.println(" - "+ linkedList.get(i));
}
LinkedList<String> reversedlinkedList = reverse(linkedList);
System.out.println("Reversed linkedList:");
for(int i = 0; i <=reversedlinkedList.size()-1; i++){
System.out.println(" - "+ reversedlinkedList.get(i));
}
}
public static LinkedList<String> reverse(LinkedList<String> linkedList){
for(int i = 0; i < linkedList.size()/2; i++){
String temp = linkedList.get(i);
linkedList.set(i, linkedList.get(linkedList.size()-1-i));
linkedList.set((linkedList.size()-1-i), temp);
}
return linkedList;
}
}
To reverse a singly linked list you should have three nodes, top, beforeTop and AfterTop. Top is the header of singly linked list, hence beforeTop would be null and afterTop would be next element of top and with each iteration move forward beforeTop is assigned top and top is assigned afterTop(i.e. top.next).
private static Node inverse(Node top) {
Node beforeTop=null, afterTop;
while(top!=null){
afterTop=top.next;
top.next=beforeTop;
beforeTop=top;
top=afterTop;
}
return beforeTop;
}
Using Recursion It's too easy :
package com.config;
import java.util.Scanner;
public class Help {
public static void main(String args[]){
Scanner sc = new Scanner(System.in);
Node head = null;
Node temp = null;
int choice = 0;
boolean flage = true;
do{
Node node = new Node();
System.out.println("Enter Node");
node.data = sc.nextInt();
if(flage){
head = node;
flage = false;
}
if(temp!=null)
temp.next = node;
temp = node;
System.out.println("Enter 0 to exit.");
choice = sc.nextInt();
}while(choice!=0);
Help.getAll(head);
Node reverse = Help.reverse(head,null);
//reverse = Help.reverse(head, null);
Help.getAll(reverse);
}
public static void getAll(Node head){
if(head==null)
return ;
System.out.println(head.data+"Memory Add "+head.hashCode());
getAll(head.next);
}
public static Node reverse(Node head,Node tail){
Node next = head.next;
head.next = tail;
return (next!=null? reverse(next,head) : head);
}
}
class Node{
int data = 0;
Node next = null;
}
Node Reverse(Node head) {
Node n,rev;
rev = new Node();
rev.data = head.data;
rev.next = null;
while(head.next != null){
n = new Node();
head = head.next;
n.data = head.data;
n.next = rev;
rev = n;
n=null;
}
return rev;
}
Use above function to reverse single linked list.
public ListNode reverseList(ListNode head) {
ListNode prev = null;
ListNode curr = head;
while (curr != null) {
ListNode nextTemp = curr.next;
curr.next = prev;
prev = curr;
curr = nextTemp;
}
return prev;
}
check more details about complexity analysis
http://javamicro.com/ref-card/DS-Algo/How-to-Reverse-Singly-Linked-List?
public static LinkedList reverseLinkedList(LinkedList node) {
if (node == null || node.getNext() == null) {
return node;
}
LinkedList remaining = reverseLinkedList(node.getNext());
node.getNext().setNext(node);
node.setNext(null);
return remaining;
}
/**
* Reverse LinkedList
* #author asharda
*
*/
class Node
{
int data;
Node next;
Node(int data)
{
this.data=data;
}
}
public class ReverseLinkedList {
static Node root;
Node temp=null;
public void insert(int data)
{
if(root==null)
{
root=new Node(data);
}
else
{
temp=root;
while(temp.next!=null)
{
temp=temp.next;
}
Node newNode=new Node(data);
temp.next=newNode;
}
}//end of insert
public void display(Node head)
{
while(head!=null)
{
System.out.println(head.data);
head=head.next;
}
}
public Node reverseLinkedList(Node head)
{
Node newNode;
Node tempr=null;
while(head!=null)
{
newNode=new Node(head.data);
newNode.next=tempr;
tempr=newNode;
head=head.next;
}
return tempr;
}
public static void main(String[] args) {
ReverseLinkedList r=new ReverseLinkedList();
r.insert(10);
r.insert(20);
r.insert(30);
r.display(root);
Node t=r.reverseLinkedList(root);
r.display(t);
}
}
public class SinglyLinkedListImpl<T> {
private Node<T> head;
public void add(T element) {
Node<T> item = new Node<T>(element);
if (head == null) {
head = item;
} else {
Node<T> temp = head;
while (temp.next != null) {
temp = temp.next;
}
temp.next = item;
}
}
private void reverse() {
Node<T> temp = null;
Node<T> next = null;
while (head != null) {
next = head.next;
head.next = temp;
temp = head;
head = next;
}
head = temp;
}
void printList(Node<T> node) {
while (node != null) {
System.out.print(node.data + " ");
node = node.next;
}
System.out.println();
}
public static void main(String a[]) {
SinglyLinkedListImpl<Integer> sl = new SinglyLinkedListImpl<Integer>();
sl.add(1);
sl.add(2);
sl.add(3);
sl.add(4);
sl.printList(sl.head);
sl.reverse();
sl.printList(sl.head);
}
static class Node<T> {
private T data;
private Node<T> next;
public Node(T data) {
super();
this.data = data;
}
}
}
public class Linkedtest {
public static void reverse(List<Object> list) {
int lenght = list.size();
for (int i = 0; i < lenght / 2; i++) {
Object as = list.get(i);
list.set(i, list.get(lenght - 1 - i));
list.set(lenght - 1 - i, as);
}
}
public static void main(String[] args) {
LinkedList<Object> st = new LinkedList<Object>();
st.add(1);
st.add(2);
st.add(3);
st.add(4);
st.add(5);
Linkedtest.reverse(st);
System.out.println("Reverse Value will be:"+st);
}
}
This will be useful for any type of collection Object.

Recursive MergeSort on a Linked List using Java

I searched on the net for a good clean and simple implentation of a merge sort algorithm in Java for a Linked List that uses recursion.
I couldn't find a nice one so Im trying to implement it here. but Im stuck.
Here is what I have so far:
public List mergeSortList(Node head, Node tail) {
if ((head == null) || (head.next == null))
return;
Node middle = this.findMiddle(head);
List left = mergeSortList(this.head, middle);
List right = mergeSortList(middle.next, tail);
return merge(left, right);
}
private List merge(List left, List right) {
List returnedList = new LinkedList();
}
private Node findMiddle(Node n) {
Node slow, fast;
slow = fast = n;
while (fast != null && fast.next.next != null) {
slow = slow.next;
fast = fast.next.next;
}
return slow;
}
Can someone help me correct any errors and fill the stubs please.
Thanks
First error is in following :-
while(fast != null && fast.next.next != null)
{
slow = slow.next;
fast = fast.next.next;
}
fast.next can be null when you do fast.next.next , considering the case when no of elements is odd.
Here is a modified code:-
while(fast != null && fast.next.next != null)
{
slow = slow.next;
if(fast.next!=null)
fast = fast.next.next;
else break;
}
Here is another modification:-
public List mergeSortList(Node head)
{
if ( (head == null) || (head.next == null))
return head;
Node middle = this.findMiddle(head);
Node first = head;
Node second = middle.next;
middle.next = null;
Node left = mergeSortList(first);
Node right = mergeSortList(second);
return merge(left, right);
}
Explanation: You donot need to pass tail to the function, You can split the list at middle into two separate list ending with null. And after recursion of two list just reconnect them to prevent loss of original list
Here is clean and simple implementation for Merge Sort on LinkedList
public class MergeSortLinkedList {
static class Node {
Node next;
int value;
Node(int value) {
this.value = value;
}
}
public static void main(String[] args) {
Node head = new Node(10);
head.next = new Node(5);
head.next.next = new Node(2);
head.next.next.next = new Node(1);
head.next.next.next.next = new Node(6);
head.next.next.next.next.next = new Node(8);
head.next.next.next.next.next.next = new Node(3);
head.next.next.next.next.next.next.next = new Node(2);
print(head);
Node sortedHead = mergeSort(head);
print(sortedHead);
}
static void print(Node head) {
Node tmp = head;
while (tmp != null) {
System.out.print(tmp.value + "->");
tmp = tmp.next;
}
System.out.println();
}
static Node getMiddle(Node head) {
if (head == null || head.next == null) {
return head;
}
Node slow = head;
Node fast = head;
while (fast.next != null && fast.next.next != null) {
fast = fast.next.next;
slow = slow.next;
}
return slow;
}
static Node sortedMerge(Node left, Node right) {
if (left == null) {
return right;
}
if (right == null) {
return left;
}
if (left.value < right.value) {
left.next = sortedMerge(left.next, right);
return left;
} else {
right.next = sortedMerge(left, right.next);
return right;
}
}
static Node mergeSort(Node head) {
if (head == null || head.next == null) {
return head;
}
Node middle = getMiddle(head);
Node middleNext = middle.next;
middle.next = null;
Node left = mergeSort(head);
Node right = mergeSort(middleNext);
return sortedMerge(left, right);
}
}
This looks like a good start. Your merge method is going to work just like any other merge sort implementation except you're dealing with lists instead of integers.
What you need to do is:
create a new list to return ('result')
compare the first element in List 'left' to the first in List 'right'
copy the smaller element to the result
advance your pointer into whichever list the smaller element came from
repeat until you hit the end of a list
copy all the remaining elements to the result
Take a stab at that (post your updated code) and we'll be happy to help you out more from there.
Solution divided in two methods,
First method is recursive method what we call from main(), then divide list using fast and slow pointer technique (fast walks 2 step when slow walks one), now call itself recursively with both the lists, and combine returned list using second method mergeSortedList, also we are calling mergeSortedList again and again within the recursion, so at the very end when there is only one element left in each list, we compare them and add together in right order.
ListNode sortList(ListNode head) {
if (head == null || head.next == null) return head;
ListNode fast = head;
ListNode slow = head;
// get in middle of the list :
while (fast.next!= null && fast.next.next !=null){slow = slow.next; fast = fast.next.next;}
fast = slow.next;
slow.next=null;
return mergeSortedList(sortList(head),sortList(fast));
}
ListNode mergeSortedList(ListNode firstList,ListNode secondList){
ListNode returnNode = new ListNode(0);
ListNode trackingPointer = returnNode;
while(firstList!=null && secondList!=null){
if(firstList.val < secondList.val){trackingPointer.next = firstList; firstList=firstList.next;}
else {trackingPointer.next = secondList; secondList=secondList.next;}
trackingPointer = trackingPointer.next;
}
if (firstList!=null) trackingPointer.next = firstList;
else if (secondList!=null) trackingPointer.next = secondList;
return returnNode.next;
}
}
Working solution in java. Go to the link below:
http://ideone.com/4WVYHc
import java.util.*;
import java.lang.*;
import java.io.*;
class Node
{
int data;
Node next;
Node(int data){
this.data = data;
next = null;
}
void append(Node head, int val){
Node temp = new Node(val);
Node cur = head;
if(head == null)
{
return;
}
while(cur.next != null)
{
cur = cur.next;
}
cur.next = temp;
return;
}
void display(){
Node cur = this;
while(cur != null)
{
System.out.print(cur.data + "->");
cur = cur.next;
}
}
}
class Ideone
{
public Node findMiddle(Node head){
if(head == null )
return null;
Node slow, fast;
slow = head;
fast = head;
while(fast != null && fast.next != null && fast.next.next != null){
slow = slow.next;
fast = fast.next.next;
}
return slow;
}
public Node merge(Node first, Node second){
Node head = null;
while(first != null && second != null){
if(first.data < second.data){
if(head == null){
head = new Node(first.data);
}
else
head.append(head,first.data);
first = first.next;
}
else if(second.data < first.data){
if(head == null){
head = new Node(second.data);
}
else
head.append(head,second.data);
second = second.next;
}
else{
if(head == null){
head = new Node(first.data);
head.append(head,second.data);
}
else{
head.append(head,first.data);
head.append(head,second.data);
}
second = second.next;
first = first.next;
}
}
while(first != null){
if(head == null){
head = new Node(first.data);
}
else
head.append(head,first.data);
first = first.next;
}
while(first != null){
if(head == null){
head = new Node(first.data);
}
else
head.append(head,first.data);
first = first.next;
}
while(second != null){
if(head == null){
head = new Node(second.data);
}
else
head.append(head,second.data);
second = second.next;
}
return head;
}
public Node mergeSort(Node head){
if(head == null)
return null;
if(head.next == null)
return head;
Node first = head;
Node mid = findMiddle(first);
Node second = mid.next;
mid.next = null;
Node left = mergeSort(first);
Node right = mergeSort(second);
Node result = merge(left, right);
return result;
}
public static void main (String[] args) throws java.lang.Exception
{
Node head = new Node(5);
head.append(head,1);
head.append(head,5);
head.append(head,1);
head.append(head,5);
head.append(head,3);
System.out.println("Unsoreted linked list:");
head.display();
Ideone tmp = new Ideone();
Node result = tmp.mergeSort(head);
System.out.println("\nSorted linked list:");
result.display();
}
}
Below is the Java version of the post to sort numbers in linked list using merge sort.
import java.util.ArrayList;
public class SortNumbersInLinkedListUsingMergeSort {
Node head;
public static void main(String[] args) {
SortNumbersInLinkedListUsingMergeSort sll = new SortNumbersInLinkedListUsingMergeSort();
// creating an unsorted linked list
sll.head = new Node(2);
sll.head.next = new Node(5);
sll.head.next.next = new Node(3);
sll.head.next.next.next = new Node(-1);
sll.head.next.next.next.next = new Node(1);
printList(sll.head);
sll.head = Merge(sll.head);
printList(sll.head);
}
//
public static Node Merge(Node head){
// if linked list has no or only one element then return
if (head == null || head.next == null){
return null;
}
// split the linked list into two halves, (front and back as two heads)
ArrayList<Node> list = splitIntoSublists(head);
// Recursively sort the sub linked lists
Merge(list.get(0));
Merge(list.get(1));
// merge two sorted sub lists
head = mergeTwoSortedLists(list.get(0), list.get(1));
return head;
}
// method to merge two sorted linked lists
public static Node mergeTwoSortedLists(Node front, Node back){
Node result;
if (front == null){
return back;
}
if (back == null){
return front;
}
if (front.data >= back.data){
result = back;
result.next = mergeTwoSortedLists(front, back.next);
}
else{
result = front;
result.next = mergeTwoSortedLists(front.next, back);
}
return result;
}
// method to split linked list into two list in middle.
public static ArrayList<Node> splitIntoSublists(Node head){
Node slowPointer;
Node fastPointer ;
Node front = null;
Node back = null;
ArrayList<Node> li = new ArrayList<Node>();
if (head == null || head.next == null){
front = head;
back = null;
}
else{
slowPointer= head;
fastPointer = head.next;
while (fastPointer != null && fastPointer.next != null){
slowPointer = slowPointer.next;
fastPointer = fastPointer.next.next;
}
front = head;
back = slowPointer.next;
slowPointer.next = null;
}
li.add(front);
li.add(back);
return li;
}
// method to print linked list
public static void printList(Node head){
Node pointer = head;
while (pointer != null){
System.out.print(pointer.data + " ");
pointer = pointer.next;
}
System.out.println();
}
}
// class to define linked list
class Node{
int data;
Node next;
public Node (int data){
this.data = data;
}
}
Here is a working example :
public class MergeSort{
public Node head = null;
public class Node {
int val;
Node next;
public Node () {//Constructor
val = 0;
next = null;
}
public Node (int i) { //constructor
val = i;
next = null;
}
}
public void insert ( int i) { //inserts node at the beginning
Node n = new Node(i);
n.next = head;
head = n;
}
public void printList (Node head) {
while (head != null) {
System.out.println (head.val);
head = head.next;
}
}
public Node sort (Node head) {
if ( head == null || head.next ==null ) return head; // no need to sort if there's no node or only one node in the Linked List
Node mid = find_Mid (head); // find middle of the LinkedList
Node sHalf = mid.next ; mid.next = null; //Splitting into two linked lists
Node h = merge ( sort(head), sort(sHalf) ); //Call merge recursively
return h;
}
public Node merge ( Node n1 , Node n2) {
Node curr = null;
if ( n1 == null )
return n2; //n1 empty
if ( n2 == null )
return n1; // n2 empty
if ( n1.val < n2.val ) {
curr=n1;
curr.next = merge (n1.next, n2); //Call merge recursively
}
else {
curr = n2;
curr.next = merge (n1, n2.next); //Call merge recursively
}
return curr;
}
public Node find_Mid (Node head) {
Node slow = head; Node fast = head;
while ( fast.next != null && fast.next.next != null ) {
slow = slow.next;
fast = fast.next.next;
}
return slow;
}
public static void main(String []args){
System.out.println("Hello World");
MergeSort m = new MergeSort ();
m.insert ( 3 );
m.insert ( 4 );
m.insert ( 16 );
m.insert ( 10 );
m.insert ( 5 );
m.insert ( 1 );
m.insert ( -5 );
m.printList(m.head);
Node n = m.find_Mid (m.head);
System.out.println("Middle is :" + n.val);
m.head = m.sort(m.head);
m.printList(m.head);
}
}

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