Develop Reference

Export multiple images in one byte array (BLOB IBM DB2) to disk

I have a column "Content" (BLOB data) in database (IBM DB2) and the data of an record same that (https://drive.google.com/file/d/12d1g5jtomJS-ingCn_n0GKMsM4RkdYzB/view?usp=sharing)
I have opened it by editor and I think that it has more than one image in this (https://i.stack.imgur.com/2biLN.png, https://i.stack.imgur.com/ZwBOs.png).
I can export an image from byte array (using C#) to my disk, but with multiple images, I don't know how to do it.
Please help me! Thanks!
Edit 1:
I have tried export it as only one image by this code:
private void readBLOB(DB2Connection conn, DB2Transaction trans)
{
try
{
string SavePath = #"D:\\MyBLOB";
long CurrentIndex = 0;
//the number of bytes to store in the array
int BufferSize = 413454;
//The Number of bytes returned from GetBytes() method
long BytesReturned;
//A byte array to hold the buffer
byte[] Blob = new byte[BufferSize];
DB2Command cmd = conn.CreateCommand();
cmd.CommandText = "SELECT ATTR0102500126 " +
" FROM JCR.ICMUT01278001 " +
" WHERE COMPKEY = 'N21E26B04900FC6B1F00000'";
cmd.Transaction = trans;
DB2DataReader reader;
reader = cmd.ExecuteReader(CommandBehavior.SequentialAccess);
if (reader.Read())
{
FileStream fs = new FileStream(SavePath + "\\" + "quang canh.jpg", FileMode.OpenOrCreate, FileAccess.Write);
BinaryWriter writer = new BinaryWriter(fs);
//reset the index to the beginning of the file
CurrentIndex = 0;
BytesReturned = reader.GetBytes(
0, //the BlobsTable column index
CurrentIndex, // the current index of the field from which to begin the read operation
Blob, // Array name to write the buffer to
0, // the start index of the array
BufferSize // the maximum length to copy into the buffer
);
while (BytesReturned == BufferSize)
{
writer.Write(Blob);
writer.Flush();
CurrentIndex += BufferSize;
BytesReturned = reader.GetBytes(0, CurrentIndex, Blob, 0, BufferSize);
}
writer.Write(Blob, 0, (int)BytesReturned);
writer.Flush(); writer.Close();
fs.Close();
}
reader.Close();
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
}
But can not view the image, it show format error => https://i.stack.imgur.com/PNS9Q.png

Your are currently asuming all BLOBS in that DB are JPEG Images. But that is clearly not the case.
Option 1: This is a faulty data
Programms that save to databases can fail.
Databases themself might fail, especially if transactions are turned off. Transactions are most likely turned off for BLOB's.
The physical disk the data was stored on might have degraded. And again, you will not get a lot of redundancy and error correction with BLOBS (plus getting use of the Error correction requires going through the proper DBMS in the first place).
Option 2: This is not a jpg
I know article about Unicode that says "[...]problem comes down to one naive programmer who didn’t understand the simple fact that if you don’t tell me whether a particular string is encoded using UTF-8 or ASCII or ISO 8859-1 (Latin 1) or Windows 1252 (Western European), you simply cannot display it correctly or even figure out where it ends."
This applies doubly, triply and quadruply to images:
this could be any number of formats that uses Interlacing.
this could could be a professional graphics programms image/project file like TIFF. Which can totally contain multiple images - up to one per layer you are working with.
this could even be a .SVG file (XML text that contains drawing orders) that was run through a .ZIP compression and a word document
this could even be a PDF, where the images are usually appended at the back (allowing you to read the text with a partial file, similar to interleaving)

How to split the ByteArray by reading from the file in C++?

I have written a Java program to write the ByteArray in to a file. And that resulting ByteArray is a resulting of these three ByteArrays-
First 2 bytes is my schemaId which I have represented it using short data type.
Then next 8 Bytes is my Last Modified Date which I have represented it using long data type.
And remaining bytes can be of variable size which is my actual value for my attributes..
So I have a file now in which first line contains resulting ByteArray which will have all the above bytes as I mentioned above.. Now I need to read that file from C++ program and read the first line which will contain the ByteArray and then split that resulting ByteArray accordingly as I mentioned above such that I am able to extract my schemaId, Last Modified Date and my actual attribute value from it.
I have done all my coding always in Java and I am new to C++... I am able to write a program in C++ to read the file but not sure how should I read that ByteArray in such a way such that I am able to split it as I mentioned above..
Below is my C++ program which is reading the file and printing it out on the console..
int main () {
string line;
//the variable of type ifstream:
ifstream myfile ("bytearrayfile");
//check to see if the file is opened:
if (myfile.is_open())
{
//while there are still lines in the
//file, keep reading:
while (! myfile.eof() )
{
//place the line from myfile into the
//line variable:
getline (myfile,line);
//display the line we gathered:
// and here split the byte array accordingly..
cout << line << endl;
}
//close the stream:
myfile.close();
}
else cout << "Unable to open file";
return 0;
}
Can anyone help me with that? Thanks.
Update
Below is my java code which will write resulting ByteArray into a file and the same file now I need to read it back from c++..
public static void main(String[] args) throws Exception {
String os = "whatever os is";
byte[] avroBinaryValue = os.getBytes();
long lastModifiedDate = 1379811105109L;
short schemaId = 32767;
ByteArrayOutputStream byteOsTest = new ByteArrayOutputStream();
DataOutputStream outTest = new DataOutputStream(byteOsTest);
outTest.writeShort(schemaId);
outTest.writeLong(lastModifiedDate);
outTest.writeInt(avroBinaryValue.length);
outTest.write(avroBinaryValue);
byte[] allWrittenBytesTest = byteOsTest.toByteArray();
DataInputStream inTest = new DataInputStream(new ByteArrayInputStream(allWrittenBytesTest));
short schemaIdTest = inTest.readShort();
long lastModifiedDateTest = inTest.readLong();
int sizeAvroTest = inTest.readInt();
byte[] avroBinaryValue1 = new byte[sizeAvroTest];
inTest.read(avroBinaryValue1, 0, sizeAvroTest);
System.out.println(schemaIdTest);
System.out.println(lastModifiedDateTest);
System.out.println(new String(avroBinaryValue1));
writeFile(allWrittenBytesTest);
}
/**
* Write the file in Java
* #param byteArray
*/
public static void writeFile(byte[] byteArray) {
try{
File file = new File("bytearrayfile");
FileOutputStream output = new FileOutputStream(file);
IOUtils.write(byteArray, output);
} catch (Exception ex) {
ex.printStackTrace();
}
}

It doesn't look like you want to use std::getline to read this data. Your file isn't written as text data on a line-by-line basis - it basically has a binary format.
You can use the read method of std::ifstream to read arbitrary chunks of data from an input stream. You probably want to open the file in binary mode:
std::ifstream myfile("bytearrayfile", std::ios::binary);
Fundamentally the method you would use to read each record from the file is:
uint16_t schemaId;
uint64_t lastModifiedDate;
uint32_t binaryLength;
myfile.read(reinterpret_cast<char*>(&schemaId), sizeof(schemaId));
myfile.read(reinterpret_cast<char*>(&lastModifiedDate), sizeof(lastModifiedDate));
myfile.read(reinterpret_cast<char*>(&binaryLength), sizeof(binaryLength));
This will read the three static members of your data structure from the file. Because your data is variable size, you probably need to allocate a buffer to read it into, for example:
std::unique_ptr<char[]> binaryBuf(new char[binaryLength]);
myfile.read(binaryBuf.get(), binaryLength);
The above are examples only to illustrate how you would approach this in C++. You will need to be aware of the following things:
There's no error checking in the above examples. You'll need to check that the calls to ifstream::read are successful and return the correct amount of data.
Endianness may be an issue, depending on the the platform the data originates from and is being read on.
Interpreting the lastModifiedDate field may require you to write a function to convert it from whatever format Java uses (I have no idea about Java).

Binary search inside a buffer

So I have implemented a working program which searches a file using the binary search method:
public int BSearch(int x1, int x2) throws IOException {
int current_key;
middle=(x1+x2)/2;
if(x1>x2) {
middle=-1; //middle==-1 is condition of 'key not found'
return middle;
}
MyFile.seek(middle*4);
current_key=MyFile.readInt();
da++;
if(current_key==key) {
return middle;
}
else if(key<current_key) {
x2=middle-1;
return BSearch(x1,x2);
}
else {
x1=middle+1;
return BSearch(x1,x2);
}
}
Now I want to transform it so it reads the file piece-by-piece (say 1KB each time) into a buffer, and then binary search that buffer. If key is not found in that buffer I read further the file and so on. I want to clarify though that the buffer is a handmade buffer like this (correct me):
byte[] buf = new byte[1024];
MyFile.read(buf);
ByteArrayInputStream bis= new ByteArrayInputStream(buf1);
DataInputStream ois= new DataInputStream(bis);
current_key=ois.readInt();
A big problem (among others) is I don't know how I'll read from a certain position of the buffer

OK I think I managed to do it by copying the buffer to a new int[] array element-by-element. I want to believe it is still faster than accessing the disc every time I want to load a buffer.

reverse chunks in a file

My basic Java problem is this: I need to read in a file by chunks, then reverse the order of the chunks, then write that out to a new file. My first (naive) attempt followed this approach:
read a chunk from the file.
reverse the bytes of the chunk
push the bytes one at a time to the front of a results list
repeat for all chunks
write result list to new file.
So this is basically a very stupid and slow way to solve the problem, but generates the correct output that I am looking for. To try to improve the situation, I change to this algorithm:
read a chunk from the file
push that chunk onto the front of a list of arrays
repeat for all chunks
foreach chunk, write to new file
And to my mind, that produces the same output. except it doesn't and I am quite confused. The first chunk in the result file matches with both methods, but the rest of the file is completely different.
Here is the meat of the Java code I am using:
FileInputStream in;
FileOutputStream out, out2;
Byte[] t = new Byte[0];
LinkedList<Byte> reversed_data = new LinkedList<Byte>();
byte[] data = new byte[bufferSize];
LinkedList<byte[]> revd2 = new LinkedList<byte[]>();
try {
in = new FileInputStream(infile);
out = new FileOutputStream(outfile1);
out2 = new FileOutputStream(outfile2);
} catch (FileNotFoundException e) {
e.printStackTrace();
return;
}
while(in.read(data) != -1)
{
revd2.addFirst(data);
byte[] revd = reverse(data);
for (byte b : revd)
{
reversed_data.addFirst(b);
}
}
for (Byte b : reversed_data)
{
out.write(b);
}
for (byte[] b : revd2)
{
out2.write(b);
}
At http://pastie.org/3113665 you can see a complete example program (a long with my debugging attempts). For simplicity I am using a bufferSize that divides evenly the size of the file so all chunks will be the same size, but this won't hold in the real world. My question is, WHY don't these two methods generate the same output? It's driving me crazy because I can't grok it.

You're constantly overwriting the data you've read previously.
while(in.read(data) != -1)
{
revd2.addFirst(data);
// ignore byte-wise stuff
}
You're adding the same object repeatedly to the list revd2, so each list node will finally contain a reference to data filled with the result of the last read. I suggest replacing that with revd2.addFirst(data.clone()).

My guess is you want to change
revd2.addFirst(data);
byte[] revd = reverse(data);
for the following so the reversed copy is added to the start of the list.
byte[] revd = reverse(data);
revd2.addFirst(revd);

Most efficient merging of 2 text files.

So I have large (around 4 gigs each) txt files in pairs and I need to create a 3rd file which would consist of the 2 files in shuffle mode. The following equation presents it best:
3rdfile = (4 lines from file 1) + (4 lines from file 2) and this is repeated until I hit the end of file 1 (both input files will have the same length - this is by definition). Here is the code I'm using now but this doesn't scale very good on large files. I was wondering if there is a more efficient way to do this - would working with memory mapped file help ? All ideas are welcome.
public static void mergeFastq(String forwardFile, String reverseFile, String outputFile) {
try {
BufferedReader inputReaderForward = new BufferedReader(new FileReader(forwardFile));
BufferedReader inputReaderReverse = new BufferedReader(new FileReader(reverseFile));
PrintWriter outputWriter = new PrintWriter(new FileWriter(outputFile, true));
String forwardLine = null;
System.out.println("Begin merging Fastq files");
int readsMerge = 0;
while ((forwardLine = inputReaderForward.readLine()) != null) {
//append the forward file
outputWriter.println(forwardLine);
outputWriter.println(inputReaderForward.readLine());
outputWriter.println(inputReaderForward.readLine());
outputWriter.println(inputReaderForward.readLine());
//append the reverse file
outputWriter.println(inputReaderReverse.readLine());
outputWriter.println(inputReaderReverse.readLine());
outputWriter.println(inputReaderReverse.readLine());
outputWriter.println(inputReaderReverse.readLine());
readsMerge++;
if(readsMerge % 10000 == 0) {
System.out.println("[" + now() + "] Merged 10000");
readsMerge = 0;
}
}
inputReaderForward.close();
inputReaderReverse.close();
outputWriter.close();
} catch (IOException ex) {
Logger.getLogger(Utilities.class.getName()).log(Level.SEVERE, "Error while merging FastQ files", ex);
}
}

Maybe you also want to try to use a BufferedWriter to cut down your file IO operations.
http://download.oracle.com/javase/6/docs/api/java/io/BufferedWriter.html

A simple answer is to use a bigger buffer, which help to reduce to total number of I/O call being made.
Usually, memory mapped IO with FileChannel (see Java NIO) will be used for handling large data file IO. In this case, however, it is not the case, as you need to inspect the file content in order to determine the boundary for every 4 lines.

If performance was the main requirement, then I would code this function in C or C++ instead of Java.
But regardless of language used, what I would do is try to manage memory myself. I would create two large buffers, say 128MB or more each and fill them with data from the two text files. Then you need a 3rd buffer that is twice as big as the previous two. The algorithm will start moving characters one by one from input buffer #1 to destination buffer, and at the same time count EOLs. Once you reach the 4th line you store the current position on that buffer away and repeat the same process with the 2nd input buffer. You continue alternating between the two input buffers, replenishing the buffers when you consume all the data in them. Each time you have to refill the input buffers you can also write the destination buffer and empty it.

Buffer your read and write operations. Buffer needs to be large enough to minimize the read/write operations and still be memory efficient. This is really simple and it works.
void write(InputStream is, OutputStream os) throws IOException {
byte[] buf = new byte[102400]; //optimize the size of buffer to your needs
int num;
while((n = is.read(buf)) != -1){
os.write(buffer, 0, num);
}
}
EDIT:
I just realized that you need to shuffle the lines, so this code will not work for you as is but, the concept still remains the same.