Suppose we have code:
public class Solution {
private String name;
private String surname;
Solution(String name, String surname) {
this.name = name;
this.surname = surname;
}
private String getPrivate() { return name; }
public String getPublic() { return surname; }
private void sout() {
new Solution("Anonim private", "Anonim public") {
void printName() {
System.out.println(getPrivate()); // Main private
//System.out.println(this.getPrivate()); // can't compile
System.out.println(super.getPrivate()); // Anonym private
System.out.println(Solution.this.getPrivate()); // Main private
System.out.println("\n");
System.out.println(getPublic()); // Anonym public
System.out.println(this.getPublic()); // Anonym public
System.out.println(super.getPublic()); // Anonym public
System.out.println(Solution.this.getPublic()); // Main public
}
}.printName();
}
public static void main(String[] args) {
new Solution("Main private", "Main public").sout();
}}
Comments - our output (by intellij idea)
Question: Why does super.getPrivate() return the string "Anonym private"?
If we look at Java documentation we will see that
If your method overrides one of its superclass's methods, you can invoke the overridden method through the use of the keyword super.
But in this case is obtained another meaning of super word: instance of inner classes. You can check it adding:
System.out.println(super.getClass());
System.out.println(this.getClass());
Question: Why does super.getPrivate() return the string "Anonym private"?
If we look at Java documentation we will see that
If your method overrides one of its superclass's methods, you can invoke the overridden method through the use of the keyword super.
But in this case is obtained another meaning of super word: instance
of inner classes.
No. The meaning of super that you quoted is the applicable one here. The context is this:
private class Solution {
[...]
private void sout() {
new Solution("Anonim private", "Anonim public") {
void printName() {
[...]
System.out.println(super.getPrivate());
You have recognized that context as an inner class's method, so the first question to answer is what is that inner class's superclass, to which the super refers? But that's easy: its superclass is Solution -- that's what the "new Solution(...)" part means.
The next question to ask is what are the properties of that instance? That is also easy: it is what results from initializing it via the constructor matching the arguments provided. Thus, it is perfectly natural and expected that super.getPrivate() reads back the first of those.
Since the inner class does not override getPrivate(), the use of super is needless -- the same result is obtained by invoking getPrivate() on the inner class instance itself, whether inside the inner class implementation or outside it.
None of that has anything to do with the containing instance of the inner class's containing class. That the containing class is also Solution is meant to confuse and challenge you. The containing instance is a separate object from the inner class instance. Its methods and variables with the same name as the inner class instances' (i.e. all of them) are hidden from the inner class instance, accessible only via the Solution.this construct.
If you compile your code on terminal with javac Solution.java, there are two files whose names are Solution.class and Solution$1.class which is the (local) inner class.
Solution.class
public class Solution {
private String name;
private String surname;
Solution(String paramString1, String paramString2) {
name = paramString1;
surname = paramString2; }
private String getPrivate() { return name; }
public String getPublic() { return surname; }
private void sout()
{
new Solution.1(this, "Anonim private", "Anonim public").printName();
}
public static void main(String[] paramArrayOfString) {
new Solution("Main private", "Main public").sout();
}
}
Solution$1.class
import java.io.PrintStream;
class Solution$1
extends Solution
{
Solution$1(Solution paramSolution, String paramString1, String paramString2) {
super(paramString1, paramString2);
}
void printName() {
System.out.println(Solution.access$000(this$0)); // Main private
System.out.println(Solution.access$000(this)); // Anonym private
System.out.println(Solution.access$000(this$0)); // Main private
System.out.println("\n");
System.out.println(getPublic()); // Anonym public
System.out.println(getPublic()); // Anonym public
System.out.println(super.getPublic()); // Anonym public
System.out.println(this$0.getPublic()); // Main public
}
}
As you can see this$0 represents enclosing class object, this represents the (local) inner class object.
Question: Why does super.getPrivate() return the string "Anonym private"?
Java opts to work like that as seen from its decompiled side ;)
I'm writing program that demonstrates the use of inheritance and I have created a variable using the super() keyword. I am now trying to place the value of that variable into a new method that calls it so that I can call that method in my main method to use its value within other classes.
Here is the relevant code:
Food class (super class)
public class Food {
//field that stores the name of the food
public String name;
//constructor that takes the name of the food as an argument
public Food(String name){
this.name = name;
}
public String getName() {
return name;
}
}
Meat class (sub class with super keyword)
public class Meat extends Food
{
public Meat() {
super("Meat");
}
public String getName() {
return //get super() value??;
}
}
Main class
public class Main {
public static void main(String[] args)
{
Wolf wolfExample = new Wolf();
Meat meatExample = new Meat();
System.out.println("************Wolf\"************");
System.out.println("Wolves eat " + meatExample.getName());
}
}
Any help is appreciated, thanks.
You could just do
public String getName() {
return super.getName();
}
Although you don't even need to override the method in the first place, because you declared the field name in super class to be public which means it can be accessed from anywhere.
Don't override public String getName() in Meat class.
The inheritance allows to inherit public and protected methods of Food in all subclasses of Food, therefore in Meat.
So Meat which IS a Food has by definition this behavior :
public String getName() {
return name;
}
which returns the name field stored in the parent class.
Overriding a method in subclass to write exactly the same code than in the parent method is useless and should not be done because it is misleading. A person which reads the code will wonder : why having overrided the method in the child class if it does the same thing than the parent class ?
Edit
Besides, if you want to access a field declared in a super class from a subclass, you should :
provide a public getter in the super class if the field is private. Here :
public String getName() {
return name;
}
use directly the field in the subclass if the field has the protected modifier.
As a general rule, you should avoid declaring instance fields with the modifier public because by default properties of a object should be protected and you should provide methods to modify the field only if needed.
So, declaring your Food class like that seems more suitable :
public class Food {
//field that stores the name of the food
private String name;
//constructor that takes the name of the food as an argument
public Food(String name){
this.name = name;
}
public String getName() {
return name;
}
}
In your Meat class, imagine you would like to add an additional information in the string returned by getName(), you could override it and why not using the field from the super class :
public class Meat extends Food {
public Meat() {
super("Meat");
}
#Override
public String getName() {
return super.getName + "(but don't abuse it)";
}
}
Here overriding the method is helpful because the behavior of the method in the child class differs from which one definedin the super class.
Simply write:
public String getName() {
return name;
}
This is because when searching for a variable named name, Java proceeds in this order:
Local variables (none)
Current class's fields (none)
Superclass's fields (found)
Super-super-class's fields (etc.)
However, you didn't need to override getName() in the subclass in the first place. If you didn't define it, then it would inherit the superclass's implementation, which corresponds exactly to the behavior you wanted. Thus you were doing extra work for no gain.
The other answers showed you how to do what you want.
But you should't do it (in real life projects)!
The most important principle in object oriented programming is encapsulation (aka information hiding). This means that the internal structure of a class should not be visible or accessible to the outside.
Therefore all member variables should be private.
Also you should avoid setter/getter methods since they just redirect the access. (except the class is a DTO without any logic of its own).
Since food class has the method getName declared as public do
public String getName() {
return super.getName();
}
I have the following
public abstract class MyData
{
private String sID;
public void setsID(String sID) {
this.sID= sID;
}
public String getsID() {
return sID;
}
}
This base class is being extended by 2 other classes
public class DataTypeOne extends MyData
{
private String sName;
public void setsName(String sName) {
this.sName= sName;
}
public String getsName() {
return sName;
}
}
public class DataTypeTwo extends MyData
{
private String sSummary;
public void setsSummary(String sSummary) {
this.sSummary= sSummary;
}
public String getsSummary() {
return sSummary;
}
}
I am initializing this class as follows
MyData oDataOne = new DataTypeOne();
MyData oDataTwo = new DataTypeTwo();
Reason for that is that I have a factory method which shall give me the class based on type (One or two)
With oDataOne & oDataTwo, I am able to access getsID() from the base class but not the getters & setters of the respective class.
How can I access those? I
You can't access a method that doesn't exist. All you've promised your Java compiler is that oDataOne and oDataTwo are MyData objects. Since the MyData class doesn't have the implementation-specific methods, you cannot ask Java to call those methods (since it doesn't think they exist).
If you want to access those methods, you need to either cast the object to a class that actually has the right methods, or you can add abstract method stubs to your base class, which will tell Java that those methods actually exist.
Type casting is simpler to write in the short term, but less clear, and you may run into more trouble down the road:
((DataTypeOne) oDataOne).getsName();
((DataTypeTwo) oDataOne).getsSummary(); // Throws ClassCastException!
Adding abstract stubs is more robust, but may not make sense if not all concrete subclasses should implement all abstract methods:
public abstract class MyData {
public abstract void setsName(String name);
public abstract String getsName();
public abstract void setsSummary(String summary);
public abstract String getsSummary();
}
public class DataTypeOne extends MyData {
public String getsName() {
// implement
}
public void setsName(String name) {
// implement
}
// Still have to implement these!!!
public String getsSummary() {
// raise an exception or something if appropriate
}
public void setsSummary(String summary) {
// raise an exception or something if appropriate
}
}
// Same for DataTypeTwo
Since you declared the variable as a MyData, you can only access the methods of MyData. You can get to the subclass methods by casting it to DataTypeOne or DataTypeTwo:
((DataTypeOne)oDataOne).getsName()
But you need to be sure it is of type DataTypeOne or you will get a ClassCastException
MyData oDataOne = new DataTypeOne();
this says, that your oDataOne object is of the type MyData. Even if it is created as a DataTypeOne, java can only be sure that it is defiantly a MyData instance.
If you are sure that the MyData instance is in reality also a DataTypeOne instance, you can cast and then access the DataTypeOne methods + the MyData methods.
To make sure that an object is of a specific type test:
if(oDataOne instanceOf DataTypeOne){
((DataTypeOne) oDataOne).getsName(); // this will return the Name if oDataOne is really of the type DataTypeOne
}
An object of type MyData has no knowledge of whether any other classes extends it or not, so there is no way to access members of those classes.
You will have to cast your object to the specific type to access the specific members.
If you find yourself in this situation, you can be pretty sure that your design is flawed. If you need to perform a specific action for each type of MyData extension, add a method, e.g specialAction() to the interface and hide the specifics in there. That eliminates the entire need to find out which subclass you are dealing with.
I just started to learn Java, so please bear with me if the answer is somewhat obvious. I did some research but no avail.
From what I understand, attributes are not overriden but only field hidden. To determine whether the attribute in the superclass or the subclass is used, Java will check the type of the reference.
Then I don't under stand the output here:
public class Super {
String str = "I'm super!\n";
public String toString() {
return str;
}
}
public class Sub extends Super {
String str = "I'm sub.\n";
}
public class TestFH {
public static void main(String[] args) {
Sub s1 = new Sub();
System.out.printf(s1.toString());
}
}
It gives me:
I'm super!
I understand that I can achieve what I want easily via method overriding. I'm just curious about what's happenning under the hood.
Thanks in advance.
When you call, s1.toString(), it's finding toString() method defined only in Super class hence using that method as super class methods are available in the sub class. Your super class method toString() is using it's own class variable str (with value initialized in super class) as the return value from the method and hence the behavior i.e. output as I'm super!.
If you want to get the output as I'm sub.\n then you need to reuse the same variable as in the super class and assign the new string value i.e. I'm sub.\n to it. Best option is to use constructors as:
public class Super {
String str = "I'm super!\n";
public Super(String stringValue){
this.str = stringValue;
}
public String toString() {
return str;
}
}
public class Sub extends Super {
public Sub(){
super("I'm sub.\n");
}
}
public class TestFH {
public static void main(String[] args) {
Sub s1 = new Sub();
System.out.printf(s1.toString());
}
}
You're hiding (shadowing) str in your child class. Since you have not overridden toString() in your child class, the call is being made in the parent class, and it sees the parent's str.
If you did this:
public class Sub extends Super {
public Sub() {
this.str = "I'm sub.\n";
}
}
It would output what you're expecting.
This call is using the super class:
Sub s1 = new Sub();
System.out.printf(s1.toString());
The reason is that Sub is not overriding str, it is just declaring another variable that happens to have the same name. In other words, sub is just hiding the variable in Super (data members are not polymorphic).
You could give them different names if they mean different things. Or maybe have the Sub access (or modify) the parent's attribute using a getter method.
you're not assigning the string literal, "I'm sub.\n" to the shared superclass field, you're creating a field local to the subclass and assigning it to that instead.
for example,
public class EncapsulationDemo {
public static void main(String[] args){
MySuperObject obj = new MySubObject();
System.out.println(obj); // prints I'm sub.
}
private static class MySuperObject{
String str = "I'm super."; // protected, can be accessed directly
// by subclasses
#Override
public String toString(){
return str;
}
}
private static class MySubObject extends MySuperObject{
MySubObject(){
super();
str = "I'm sub."; // assign to superclass field
}
}
}
for more information, please see Controlling Access to Members of a Class.
This is a question I was asked in an interview: I have class A with private members and Class B extends A. I know private members of a class cannot be accessed, but the question is: I need to access private members of class A from class B, rather than create variables with the same value in class B.
The interviewer was either testing your knowledge of access modifiers, or your approach to changing existing classes, or both.
I would have listed them (public, private, protected, package private) with an explanation of each. Then gone on to say that class A would need to be modified to allow access to those members from class B, either by adding setters and getters, or by changing the access modifiers of the members. Or class B could use reflection. Finally, talk about the pros and cons of each approach.
Reflection? Omitting imports, this should work:
public class A {
private int ii = 23;
}
public class B extends A {
private void readPrivateSuperClassField() throws Exception {
Class<?> clazz = getClass().getSuperclass();
Field field = clazz.getDeclaredField("ii");
field.setAccessible(true);
System.out.println(field.getInt(this));
}
public static void main(String[] args) throws Exception {
new B().readPrivateSuperClassField();
}
}
It'll not work if you do something like that before the of invocation readPrivateSuperClassField();:
System.setSecurityManager(new SecurityManager() {
#Override
public void checkMemberAccess(Class<?> clazz, int which) {
if (clazz.equals(A.class)) {
throw new SecurityException();
} else {
super.checkMemberAccess(clazz, which);
}
}
});
And there are other conditions under which the Reflection approach won't work. See the API docs for SecurityManager and AccessibleObject for more info. Thanks to CPerkins for pointing that out.
I hope they were just testing your knowledge, not looking for a real application of this stuff ;-) Although I think an ugly hack like this above can be legit in certain edge cases.
The architecture is broken. Private members are private because you do not want them accessed outside the class and friends.
You can use friend hacks, accessors, promote the member, or #define private public (heh). But these are all short term solutions - you will probably have to revisit the broken architecture at some stage.
By using public accessors (getters & setters) of A's privates members ...
You cannot access private members from the parent class. You have make it protected or have protected/public method that has access to them.
EDIT : It is true you can use reflection. But that is not usual and not good idea to break encapsulation.
A nested class can access to all the private members of its enclosing class—both fields and methods. Therefore, a public or protected nested class inherited by a subclass has indirect access to all of the private members of the superclass.
public class SuperClass
{
private int a = 10;
public void makeInner()
{
SubClass in = new SubClass();
in.inner();
}
class SubClass
{
public void inner()
{
System.out.println("Super a is " + a);
}
}
public static void main(String[] args)
{
SuperClass.SubClass s = new SuperClass().new SubClass();
s.inner();
}
}
If I'm understanding the question correctly, you could change private to protected. Protected variables are accessible to subclasses but behave like private variables otherwise.
By using setters and getters u can access it
From JLS §8.3. Field Declarations:
A private field of a superclass might be accessible to a subclass - for example, if both classes are members of the same class. Nevertheless, a private field is never inherited by a subclass.
I write the example code:
public class Outer
{
class InnerA
{
private String text;
}
class InnerB extends InnerA
{
public void setText(String text)
{
InnerA innerA = this;
innerA.text = text;
}
public String getText()
{
return ((InnerA) this).text;
}
}
public static void main(String[] args)
{
final InnerB innerB = new Outer().new InnerB();
innerB.setText("hello world");
System.out.println(innerB.getText());
}
}
The explanation of the accessibility of InnerA.text is here JLS §6.6.1. Determining Accessibility:
Otherwise, the member or constructor is declared private, and access is permitted if and only if it occurs within the body of the top level class (§7.6) that encloses the declaration of the member or constructor.
You can use the setters and getters of class A. Which gives same feeling as if You are using a class A's object.
Have you thought about making them protected ? Just to be sure you are aware of this option, if you are then pardon me for bringing up this trivia ;)
Private members cant be accessed in derived class
If you want to access means you can use getter and setter methods.
class A
{
private int a;
void setA(int a)
{
this.a=a;
}
int getA()
{
return a;
}
}
Class B extends A
{
public static void main(String[] arg)
{
B obj= new B();
obj.setA(10);
System.out.println("The value of A is:"+obj.getA());
}
}
Private will be hidden until you have been given the right access to it. For instance Getters or setters by the programmer who wrote the Parent. If they are not visible by that either then accept the fact that they are just private and not accessible to you. Why exactly you want to do that??
I don't know about Java, but in some languages nested types can do this:
class A {
private string someField;
class B : A {
void Foo() {
someField = "abc";
}
}
}
Otherwise, use an accessor method or a protected field (although they are often abused).
A private member is accessible in subclass in a way that you cannot change the variable, but you are able to access the variable as read only.
Obviously, making them protected, or adding setters/getters is the preferred technique. Reflection is a desperation option.
Just to show off to the interviewer, IF "access" means read access, and IF Class A generates XML or JSON etc., you could serialize A and parse the interesting fields.
Class A
{
private int i;
int getValue()
{
return i;
}
}
class B extends A
{
void getvalue2()
{
A a1= new A();
sop(a1.getValue());
}
}
To access private variables of parent class in subclass you can use protected or add getters and setters to private variables in parent class..
You can't access directly any private variables of a class from outside directly.
You can access private member's using getter and setter.
Ways to access the superclass private members in subclass :
If you want package access just change the private fields to protected. It allows access to same package subclass.
If you have private fields then just provide some Accessor Methods(getters) and you can access them in your subclass.
You can also use inner class e.g
public class PrivateInnerClassAccess {
private int value=20;
class InnerClass {
public void accessPrivateFields() {
System.out.println("Value of private field : " + value);
}
}
public static void main(String arr[])
{
PrivateInnerClassAccess access = new PrivateInnerClassAccess();
PrivateInnerClassAccess.InnerClass innerClass = access.new InnerClass();
innerClass.accessPrivateFields();
}
}
4 .You can also use Reflection e.g
public class A {
private int value;
public A(int value)
{
this.value = value;
}
}
public class B {
public void accessPrivateA()throws Exception
{
A a = new A(10);
Field privateFields = A.class.getDeclaredField("value");
privateFields.setAccessible(true);
Integer value = (Integer)privateFields.get(a);
System.out.println("Value of private field is :"+value);
}
public static void main(String arr[]) throws Exception
{
B b = new B();
b.accessPrivateA();
}
}
You can use Accessors (getter and setter method) in your Code.
By using setter method you can use else with the help of refection you can use private member of class by setting that member say a -
take a from class
and set a.setAccessible(true);
You may want to change it to protected.
Kindly refer this
https://docs.oracle.com/javase/tutorial/java/javaOO/accesscontrol.html
If this is something you have to do at any cost just for the heck of doing it you can use reflection. It will give you list of all the variables defined in the class- be it public, private or protected. This surely has its overhead but yes, it is something which will let you use private variables. With this, you can use it in any of the class. It does not have to be only a subclass
Please refer to the example below. This may have some compilation issues but you can get the basic idea and it works
private void getPropertiesFromPrivateClass(){
Field[] privateVariablesArray = PrivateClassName.getClass().getDeclaredFields();
Set<String> propertySet = new HashSet<String>();
Object propertyValue;
if(privateVariablesArray.length >0){
for(Field propertyVariable :privateVariablesArray){
try {
if (propertyVariable.getType() == String.class){
propertyVariable.setAccessible(true);
propertyValue = propertyVariable.get(envtHelper);
System.out.println("propertyValue");
}
} catch (IllegalArgumentException illegalArgumentException) {
illegalArgumentException.printStackTrace();
} catch (IllegalAccessException illegalAccessException) {
illegalAccessException.printStackTrace();
}
}
Hope this be of some help.
Happy Learning :)
Below is the example for accessing the private members of superclass in the object of subclass.
I am using constructors to do the same.
Below is the superclass Fruit
public class Fruit {
private String type;
public Fruit() {
}
public Fruit(String type) {
super();
this.type = type;
}
public String getType() {
return type;
}
public void setType(String type) {
this.type = type;
}
}
Below is subclass Guava which is inheriting from Fruit
public class Guava extends Fruit{
private String name;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Guava(String name,String type) {
super(type);
this.name=name;
}
}
Below is the main function where we are creating an object of subclass and also displaying the member of superclass.
public class Main {
public static void main(String[] args) {
Guava G1=new Guava("kanpuria", "red");
System.out.println(G1.getName()+" "+G1.getType());
}
}
Note that a private field of a superclass might be accessible to a subclass (for example,if both classes are memebers of the same class),Nevertheless,a private field is never inherited
by a subclass
Simple!!!
public class A{
private String a;
private String b;
//getter and setter are here
}
public class B extends A{
public B(String a, String b){ //constructor
super(a,b)//from here you got access with private variable of class A
}
}
thanks
Directly we can't access it. but Using Setter and Getter we can access,
Code is :
class AccessPrivate1 {
private int a=10; //private integer
private int b=15;
int getValueofA()
{
return this.a;
}
int getValueofB()
{
return this.b;
}
}
public class AccessPrivate{
public static void main(String args[])
{
AccessPrivate1 obj=new AccessPrivate1();
System.out.println(obj.getValueofA()); //getting the value of private integer of class AccessPrivate1
System.out.println(obj.getValueofB()); //getting the value of private integer of class AccessPrivate1
}
}
Modifiers are keywords that you add to those definitions to change their meanings. The Java language has a wide variety of modifiers, including the following:
Java Access Modifiers
Non Access Modifiers
To use a modifier, you include its keyword in the definition of a class, method, or variable. The modifier precedes the rest of the statement.
There is more information here:
http://tutorialcorejava.blogspot.in/p/java-modifier-types.html