I'm not sure why I'm getting this error. I'm trying to write a test and I'm getting this error on line artistLabelRepository.save(artistLabel1); in ArtistLabelRepositoryTestIT
Can not set com.pandora.label.entity.Label field com.pandora.label.entity.ArtistLabelId.label to java.lang.Long
These are the tables. the tables are already created and populated. I can alter the tables, but would like to not delete them and recreate them.
CREATE TABLE label (
id BIGSERIAL PRIMARY KEY,
name TEXT NOT NULL UNIQUE,
parent_label_id BIGINT REFERENCES label(id)
)
CREATE INDEX album_uid_idx ON album_label(id);
CREATE TABLE artist_label (
artist_id VARCHAR(60) NOT NULL,
label_id BIGINT NOT NULL,
PRIMARY KEY (artist_id, label_id)
);
CREATE INDEX artist_label_idx ON artist_label(label_id);
ALTER TABLE artist_label ADD CONSTRAINT artist_label_fk FOREIGN KEY (label_id) REFERENCES label(id);
these are the Entities
class ArtistLabelId implements Serializable {
private String artistId;
private Label label;
public ArtistLabelId() {
// no arg constructor for JPA
}
public ArtistLabelId(String artistId, Label label) {
this.artistId = artistId;
this.label = label;
}
// setters and getters
}
#Entity
#IdClass(ArtistLabelId.class)
#Table(name="artist_label",
indexes = {#Index(name = "artist_label_idx", columnList = "artist_id")})
public class ArtistLabel {
#Id
#Column (name = "artist_id")
private String artistId;
#Id
#ManyToOne
#JoinColumn(name = "label_id")
private Label label;
public ArtistLabel() {
// no arg constructor for JPA
}
public ArtistLabel(String artistId, Label label) {
this.artistId = artistId;
this.label = label;
}
// setters and getters
}
#Entity
#Table(name="label")
public class Label {
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator="label_generator")
#SequenceGenerator(name= "label_generator", sequenceName = "label_id_seq", allocationSize = 1)
#Column(name = "id")
private long labelId;
#Column (name = "name")
private String name;
#ManyToOne
#JoinColumn(name = "parent_label_id")
private Label parentLabel; //references parent label
#Column(name = "create_date")
private Timestamp createDate;
#Column(name = "last_modified")
private Timestamp lastModified;
public Label(){
//no-arg constructor for JPA
}
public Label(String name, Label parentLabel){
this.name = name;
this. parentLabel = parentLabel;
}
public Label(long labelId, String name, Label parentLabel){
this.labelId = labelId;
this.name = name;
this.parentLabel = parentLabel;
}
// setters and getters
}
this is the repository
#Repository
public interface ArtistLabelRepository extends CrudRepository<ArtistLabel, Long> {}
and this is the test. i'm trying to save an artistLabel artistLabelRepository.save(artistLabel1);
#ActiveProfiles(value="test")
#SpringBootTest(classes = {Application.class})
public class ArtistLabelRepositoryTestIT {
#Autowired
ArtistLabelRepository artistLabelRepository;
#Autowired
LabelRepository labelRepository;
#Test
public void testFindByLabelId(){
Label label = new Label(123L, "label1", null);
labelRepository.save(label);
ArtistLabel artistLabel1 = new ArtistLabel("artistId1", label);
artistLabelRepository.save(artistLabel1);
}
}
Related
So, I'm trying to persist an entity in the database that has a composite key, declared using the #IdClass annotation, which one of the ID keys I have turned into an object so ensure some validation of the data.
Before, when this ID was just a String, it was working without any problems, but now that I have changed it's type, it seens that Hibernate can't determine it's type in the database.
I found a question with a problem that was almost exactly the same as the mine, here. After I added the #Column annotation to the fields in the IdClass, I feel that the Hibernate could determine the type of the field in the database, but now it fails to perform the conversion.
I already have the converter class with the #Converter annotation and implementing the AttributeConverter interface, but I think that it isn't being reached by the Spring/Hibernate.
The involved classes bellow:
The converter
#Converter
public class ChapterNumberConverter implements AttributeConverter<ChapterNumber, String> {
#Override
public String convertToDatabaseColumn(ChapterNumber attribute) {
String value = attribute.getValue();
return value;
}
#Override
public ChapterNumber convertToEntityAttribute(String dbData) {
ChapterNumber chapterNumber = new ChapterNumber(dbData);
return chapterNumber;
}
}
The composite ID class
public class ChapterID implements Serializable {
private static final long serialVersionUID = 4324952545057872260L;
#Column
private Long id;
#Column
#Convert(converter = ChapterNumberConverter.class)
private String number;
#Column
private Long publisher;
#Column
private Long manga;
public ChapterID() {
}
public ChapterID(Long id, String number, Long publisher, Long manga) {
this.id = id;
this.number = number;
this.publisher = publisher;
this.manga = manga;
}
// ... getters and setters
}
The entity class
#Entity
#Table(name = "chapter", uniqueConstraints = #UniqueConstraint(columnNames = {"number", "publisher_id", "manga_id"}))
#IdClass(ChapterID.class)
public class Chapter {
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#Id
#Convert(converter = ChapterNumberConverter.class)
private ChapterNumber number;
#Id
#ManyToOne
#JoinColumn(name = "publisher_id")
private Publisher publisher;
#Id
#ManyToOne
#JoinColumn(name = "manga_id")
private Manga manga;
#Column(nullable = false)
#Convert(converter = ChapterLanguageEnumConverter.class)
private ChapterLanguage language;
public Chapter() {
}
public Chapter(ChapterNumber chapterNumber, Publisher publisher, Manga manga, ChapterLanguage language) {
this.number = chapterNumber;
this.publisher = publisher;
this.manga = manga;
this.language = language;
}
public Chapter(String chapterNumber, Publisher publisher, Manga manga, ChapterLanguage language) {
this(new ChapterNumber(chapterNumber), publisher, manga, language);
}
// ... getters and setters
}
I just want to validate the number field in the entity class, so, if there is another way to do this without using a custom type, otherwise, if anyone knows what I can do to teach correctly the Hibernate how to persist this field, tell me please 😢
I have to map a composite PK with JPA in an Oracle DB.
I've followed other SO questions with relation to this tutorial but I'm still getting the following error:
java.sql.SQLSyntaxErrorException: ORA-00904: "COMPOSITEI0_"."NAME_1": Invalid Identifier (where NAME_1 relates to the name of one of the columns which are part of the PK)
This is my entity (real names not mentioned for data protection reasons):
#Entity
#Table(schema = "SCHEMA", name = "TABLE")
public class CompositeIdEntity {
#Column(name = "NAME1")
private String name1;
#Column(name = "NAME2")
private String name2;
#Column(name = "NAME3")
private String name3;
#EmbeddedId
CompositePrimaryKeyTableEmbeddable id;
public CompositePrimaryKeyTableEmbeddable getId() {
return this.id;
}
public void setId(CompositePrimaryKeyTableEmbeddable id) {
this.id = id;
}
// other getters and setters
My #Embeddable id class:
#Embeddable
public class CompositePrimaryKeyTableEmbeddable implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
#Column(name="name1")
private String name1;
#Column(name="name2")
private String name2;
public CompositePrimaryKeyTableEmbeddable() {
super();
}
public CompositePrimaryKeyTableEmbeddable(String name1, String name2) {
this.name1 = name1;
this.name2 = name2;
}
My #Repository:
#Repository
public interface CompositeIdDao extends JpaRepository<CompositeIdEntity, CompositePrimaryKeyTableEmbeddable> {
}
And finally call to the DB, which only returns null because it's just a test to see if it all works together:
public CompositeIdEto saveCompositeId() {
CompositeIdEntity compositeIdEto = new CompositeIdEntity();
compositeIdEto.setname3("New");
compositeIdEto.setId(new CompositePrimaryKeyTableEmbeddable("ERR", "ER"));
this.compositeIdDao.save(compositeIdEto);
return null;
}
It seems you are duplicating the name1 and name2 columns by declaring them once
in the entity itself and later in the embeddable.
You seem to only need the id embeddable and the name3 declaration in the entity:
#Entity
#Table(schema = "SCHEMA", name = "TABLE")
public class CompositeIdEntity {
#EmbeddedId
CompositePrimaryKeyTableEmbeddable id;
#Column(name = "NAME3")
private String name3;
I'm trying to generate ddl from existing annotated entities using "JPA tools --> Generate Tables from Entities..." in Eclipse Kepler. When I run the task, I get a file with sql scripts to run. The problem is that the order of the columns in the table creation statement fails to comply with the order of the attributes in the class definition.
Example:
#Entity
#Table(name = "news", catalog = "myDatabase")
public class News implements java.io.Serializable {
private long id;
private String newsTitle;
private String newsTitle2;
private String newsText;
private Date created;
#Id
#GeneratedValue
#Column(name = "news_id", unique = true, nullable = false)
public long getId() {
return this.id;
}
public void setId(long id) {
this.id = id;
}
#Column(name = "news_title")
public String getNewsTitle() {
return this.newsTitle;
}
public void setNewsTitle(String newsTitle) {
this.newsTitle = newsTitle;
}
#Column(name = "news_title2")
public String getNewsTitle2() {
return this.newsTitle2;
}
public void setNewsTitle2(String newsTitle2) {
this.newsTitle2 = newsTitle2;
}
#Lob
#Column(name = "news_text")
public String getNewsText() {
return this.newsText;
}
public void setNewsText(String newsText) {
this.newsText = newsText;
}
#Temporal(TemporalType.TIMESTAMP)
#Column(name = "created")
public Date getCreated() {
return this.created;
}
public void setCreated(Date created) {
this.created = created;
}
}
Script:
CREATE TABLE myDatabase.news (
news_id BIGINT NOT NULL UNIQUE, created DATETIME, news_text LONGTEXT,
news_title VARCHAR(255), news_title2 VARCHAR(255), PRIMARY KEY (news_id))
How can I get the scripts with the order of the columns aligned with the java class?
Thank you very much
Stefano
This is not possible due to the abstraction approach in JPA. Theoretically you don't know the kind of database below nor whether the order is important there.
I am new to hibernate and having a tough time trying to wrap my head around setting up Joined inheritance with composite Primary Key. With my current setup, I get a:
JDBCException: could not insert: LandHolidayPackage
I am essentially looking for two things:
Are the inheritance annotations in place ?
Is the composite PK setup properly ?
DB Design:
Reference
Here are my classes and the annotations involved:
#Entity
#Table(name = "HOLIDAYPACKAGE")
public final class HolidayPackage {
private Integer idPackage;
private String name;
private Set<HolidayPackageVariant> holidayPackageVariants = new HashSet<HolidayPackageVariant>(0);
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "IDHOLIDAYPACKAGE", nullable = false)
public Integer getIdPackage() {
return idPackage;
}
#OneToMany(fetch=FetchType.LAZY, cascade={CascadeType.ALL}, mappedBy = "holidayPackage")
public Set<HolidayPackageVariant> getHolidayPackageVariants() {
return holidayPackageVariants;
}
// ommitted other part of the code
}
#Entity
#Inheritance(strategy=InheritanceType.JOINED)
#Table(name="HOLIDAYPACKAGEVARIANT")
public abstract class HolidayPackageVariant {
private Integer idHolidayPackageVariant;
private HolidayPackage holidayPackage;
private String typeHolidayPackage;
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="IDHOLIDAYPACKAGEVARIANT", nullable=false)
public Integer getIdHolidayPackageVariant() {
return idHolidayPackageVariant;
}
#ManyToOne(fetch=FetchType.LAZY, cascade={CascadeType.ALL})
#JoinColumn(name="IDHOLIDAYPACKAGE", nullable=false)
public HolidayPackage getHolidayPackage() {
return holidayPackage;
}
#Column(name="TYPEHOLIDAYPACKAGE", nullable=true)
public String getTypeHolidayPackage() {
return typeHolidayPackage;
}
// ommitted setters, equals hashCode
}
#Entity
#Table(name="LANDHOLIDAYPACKAGEVARIANT")
public final class LandHolidayPackageVariant extends HolidayPackageVariant{
private static final String LAND = "LAND";
protected LandHolidayPackageVariant() {}
public LandHolidayPackageVariant(HolidayPackage holidayPackage) {
super(holidayPackage, LAND);
}
}
#Entity
#Table(name="FLIGHTHOLIDAYPACKAGEVARIANT")
public final class FlightHolidayPackageVariant extends HolidayPackageVariant{
private static final String FLIGHT = "FLIGHT";
private Destination originCity;
protected FlightHolidayPackageVariant(){}
public FlightHolidayPackageVariant(HolidayPackage holidayPackage,
Destination originCity) {
super(holidayPackage, FLIGHT);
setOriginCity(originCity);
}
#ManyToOne(fetch=FetchType.LAZY, cascade={CascadeType.ALL})
#JoinColumn(name="IDDESTINATION", nullable=false)
public Destination getOriginCity() {
return originCity;
}
// ommited other setters etc functions
}
You annotated the properties in stead of the fields. JPA by default tries to access the fields. If you want JPA to use the fields you have to annotate the class with #AccessType(AccessType.Field).
I am trying to map the following table
CREATE TABLE Person (
p_id varchar(255) not null,
p_name varchar(255 not null,
p_post_code varchar(12) not null,
primary key (p_id, p_name),
);
Usually when i map an Entity to the above table i would do something like this (for single column primary keys):
private int p_id;
private String p_name;
private String p_post_code;
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="p_id")
public Long getPId() {
return p_id;
}
public void setPId(int p_id) {
this.p_id = p_id;
}
#Column(name="p_name")
public String getPname() {
return p_name;
}
public void setPname(String string) {
this.p_name = string;
}
#Column(name="p_post_code")
public String getPostCode() {
return p_post_code;
}
public void setPostCode(String string) {
this.p_post_code = string;
}
The above works if the primary key is a single column (i.e. p_id) and the value for this column is generated in the database.
How would i modify the above to map it so that both p_id and p_name are the primary key.
Also, how would this work, if the composite key is a foreign key in another table.
I am trying to google for some examples but i cant find a simple example and most seem to be using the XML based configuration.
When using composite keys with JPA you need to use an embedded class as an id.
In your case you would have a person class and a primary key class for person:
#entity
public class Person
{
#EmbeddedId
private PersonPK key;
#Column(name="p_post_code", nullable = false)
private String p_post_code;
//....
}
#Embeddable
public class PersonPK
{
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="p_id");
private Long p_id;
#Column(name="p_name")
private String p_name;
public PersonPK(String name)
{
p_name = name;
}
//....
}
Using a class for the person's name (so the name is also a foreign key):
#entity
public class Person
{
#EmbeddedId
private PersonPK key;
#MapsId(value="p_name_id")
#ManyToOne
#JoinColumn(name = "p_name_id", referencedColumnName = "id")
private Name p_name;
#Column(name="p_post_code", nullable = false)
private String p_post_code;
//....
}
#Embeddable
public class PersonPK
{
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="p_id");
private Long p_id;
#Column(name="p_name_id")
private Long p_name_id;
public PersonPK(Name name)
{
p_name_id = name.getId();
}
//....
}
#Entity
public class Name
{
#Id
#GeneratedValue(some generation strategy here)
#Column(name="id")
private Long id;
#Column(name="name")
private String name;
//....
}