copy Resource folders files after deployment in spring boot app - java

private static void copyRequiredCBAFiles(String sourceFileUrl, Path targetDirectory, String fileName, Boolean rename) throws IOException {
File source = new File(new ClassPathResource(sourceFileUrl).getFile().getAbsolutePath());
File destination = targetDirectory.toFile();
for (File file : source.listFiles()) {
if (file.isFile()) {
if (rename && (StringUtils.equalsIgnoreCase(file.getName(),"template.txt") || StringUtils.equalsIgnoreCase(file.getName(), "mapping.json"))) {
copyAndRenameFileToDirectory(file, destination, fileName);
} else {
FileUtils.copyFileToDirectory(file, destination);
}
}
}
}
i have some files and subfolders inside resouces folder, Now after deploy the code im not able to access it im getting null pointer exception. Is it possible to access those files and folders.

Related

java.nio.file.AccessDeniedException error?

Im trying to zip my created folder. Right now im testing localy and it create folder but after that i want to zip it.
This is my code for zip:
public static void pack(final String sourceDirPath, final String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p))) {
Path pp = Paths.get(sourceDirPath);
Files.walk(pp).filter(path -> !Files.isDirectory(path)).forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
} }
But im getting an error AccessDeniedException. Is there any option to zip created folder, i dont want to zip file because in that folder i will have subfolders, so i want to zip main folder. Any suggestion how can i achive that?
According to:
Getting "java.nio.file.AccessDeniedException" when trying to write to a folder
I think you should add the filename and the extension to your 'zipFilePath', for example: "C:\Users\XXXXX\Desktop\zippedFile.zip"

Deploy java spring-boot app *.jar to heroku with other files in root folder

I have a spring boot app as qsysprereg2-1.0.jar. I pushed into heroku git already compiled jar file + Procfile + folder "config" with files for my app as "config/config.properties". Just some properties.
In Gradle I have only:
apply plugin: 'java'
task stage() {
println("Go stage...")
}
All compiled and deployed successfully.
In result I have error:
java.io.FileNotFoundException: config/config.properties (No such file or directory)
Of course, because:
Running bash on ⬢ qprereg... up, run.9546 (Free)
~ $ ls
Procfile qsysprereg2-1.0.jar system.properties
Where is no folder "config" from git. But "config/config.properties" had been pushed into git.
How to add the folder with files to deploy artifacts?
Sorry, but I did not find a nice solution. I made some tricks. I put all my config files in jar as resources. During starting the app I am checking the files outside jar on dick then coping from resources to dist. New files are keeping on disk without problems. Code for that:
public static void main(String[] args) {
try {
prepareConfig();
} catch (IOException ex) {
log.error("Config prepare fail.", ex);
log.throwing(ex);
throw new RuntimeException(ex);
}
SpringApplication.run(Application.class, args);
}
private static void prepareConfig() throws IOException {
File dir = new File("config");
if (!dir.exists() || !dir.isDirectory()) {
log.info("Create config directory");
Files.createDirectory(dir.toPath());
}
makeReady("config/config1.properties");
makeReady("config/config2.properties");
makeReady("config/config3.properties");
makeReady("config/configN.properties");
}
private static void makeReady(String fileName) throws IOException {
File file = new File(fileName);
if (!file.exists()) {
log.info("Create config file '{}'", file.getName());
try (final InputStream stream = Application.class.getResourceAsStream("/" + fileName)) {
Files.copy(stream, file.toPath());
}
}
}

Java android delete File

I want to delete a file (pdf file) I did this :
boolean deleted = filesList.get(pos).delete();
But when I look in my phone I see this file , but my application doesn't see this file
To delete a file from a directory, you can use this method:
public static void deleteFile(File directory, String fileName) {
if (directory.isDirectory()) {
for(File file : directory.listFiles()) {
if (file.getName().contains(fileName)) {
if (file.isFile()) {
if (file.exists()) {
file.delete();
}
}
}
}
}
}
And if you want to delete the entire directory:
public static void deleteDirectory(File directory) {
if (directory.isDirectory())
for (File child : directory.listFiles())
deleteDirectory(child);
directory.delete();
}
As mentioned by ylmzekrm1223, you should provide permissions to read and write storage in your AndroidManifest.xml, before attempting to delete a file or a directory.
Your code doesn't delete a file from the file system. It just deletes an element from the list.
Check this for more
delete file in sdcard
To delete a file from the file system, first you need to provide Permission to read and write local storage in your AndroidManifest.xml
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE">
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>
Then, in your code,
String path = "/mnt/sdcard/test.pdf";
File mFile = new File(path);
mFile.delete();

How to get the root path of my project?

I have JSP projects that run in Tomcat developed in Eclipse.
I want to have some files which I store inside the project.
Here is the project structure that I have:
.settings
build
data
ImportedClasses
src
WebContent
.classpath
.project
I want to access the data folder from my code in JSP file which located in WebContent.
Tried some code below:
File userDataDirFile = new File ( "data" );
String path = userDataDirFile.getAbsolutePath();
prints
C:\Program Files\eclipse\data\users
Then
this.getClass().getClassLoader().getResource("").getPath()
prints
C:/Workspaces/.metadata/.plugins/org.eclipse.wst.server.core/tmp0/wtpwebapps/survey/WEB-INF/classes/
Another one:
System.getProperty("user.dir")
prints
C:\Program Files\eclipse
There is no code that I tried (I think the 2nd solution supposed to work, but it doesn't) can locate me to root folder of my project. Anyone can advise?
String caminhoProjeto = Thread.currentThread().getContextClassLoader().getResource("").getPath();
This is like "src" path, but is the "classes" path of binaries files context after deployment and runtime.
My class for example of the necessarie use of this way "root dir of project":
PropertiesReader.java:
public class PropertiesReader {
public static String projectPath = Thread.currentThread().getContextClassLoader().getResource("").getPath();
public static String propertiesPath = "/META-INF/";
public static Properties loadProperties(String propertiesFileName) throws IOException {
Properties p = new Properties();
p.load(new FileInputStream(projectPath + propertiesPath + propertiesFileName));
return p;
}
public static String getText(String propertiesFileName, String propertie) {
try {
return loadProperties(propertiesFileName).getProperty(propertie);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return propertie;
}
}
PersonRegistration.java:
#ManagedBean
public class PersonRegistration {
private Integer majority = Integer.parseInt(PropertiesLeitor.getText("Brasil.properties", "pessoa.maioridade"));
}
Brasil.properties (within src / META-INF):
pessoa.maioridade = 18
Edit : File that are not in WebContent will not be deployed with your war. you have to put files used in you code inside the WebContent and try with ServletContext which point to the root folder of the your web application :
if your file is at the same folder as WEB-INF then :
ServletContext context = getContext();
String fullPath = context.getRealPath("/data");
by the way if you don't want to give direct access to data file it's recommanded to put it in WEB-INF so that no one can have access to them directly.

How to check if a folder exists?

I am playing a bit with the new Java 7 IO features. Actually I am trying to retrieve all the XML files in a folder. However this throws an exception when the folder does not exist. How can I check if the folder exists using the new IO?
public UpdateHandler(String release) {
log.info("searching for configuration files in folder " + release);
Path releaseFolder = Paths.get(release);
try(DirectoryStream<Path> stream = Files.newDirectoryStream(releaseFolder, "*.xml")){
for (Path entry: stream){
log.info("working on file " + entry.getFileName());
}
}
catch (IOException e){
log.error("error while retrieving update configuration files " + e.getMessage());
}
}
Using java.nio.file.Files:
Path path = ...;
if (Files.exists(path)) {
// ...
}
You can optionally pass this method LinkOption values:
if (Files.exists(path, LinkOption.NOFOLLOW_LINKS)) {
There's also a method notExists:
if (Files.notExists(path)) {
Quite simple:
new File("/Path/To/File/or/Directory").exists();
And if you want to be certain it is a directory:
File f = new File("/Path/To/File/or/Directory");
if (f.exists() && f.isDirectory()) {
...
}
To check if a directory exists with the new IO:
if (Files.isDirectory(Paths.get("directory"))) {
...
}
isDirectory returns true if the file is a directory; false if the file does not exist, is not a directory, or it cannot be determined if the file is a directory or not.
See: documentation.
Generate a file from the string of your folder directory
String path="Folder directory";
File file = new File(path);
and use method exist.
If you want to generate the folder you sould use mkdir()
if (!file.exists()) {
System.out.print("No Folder");
file.mkdir();
System.out.print("Folder created");
}
You need to transform your Path into a File and test for existence:
for(Path entry: stream){
if(entry.toFile().exists()){
log.info("working on file " + entry.getFileName());
}
}
There is no need to separately call the exists() method, as isDirectory() implicitly checks whether the directory exists or not.
import java.io.File;
import java.nio.file.Paths;
public class Test
{
public static void main(String[] args)
{
File file = new File("C:\\Temp");
System.out.println("File Folder Exist" + isFileDirectoryExists(file));
System.out.println("Directory Exists" + isDirectoryExists("C:\\Temp"));
}
public static boolean isFileDirectoryExists(File file)
{
if (file.exists())
{
return true;
}
return false;
}
public static boolean isDirectoryExists(String directoryPath)
{
if (!Paths.get(directoryPath).toFile().isDirectory())
{
return false;
}
return true;
}
}
We can check files and thire Folders.
import java.io.*;
public class fileCheck
{
public static void main(String arg[])
{
File f = new File("C:/AMD");
if (f.exists() && f.isDirectory()) {
System.out.println("Exists");
//if the file is present then it will show the msg
}
else{
System.out.println("NOT Exists");
//if the file is Not present then it will show the msg
}
}
}
File sourceLoc=new File("/a/b/c/folderName");
boolean isFolderExisted=false;
sourceLoc.exists()==true?sourceLoc.isDirectory()==true?isFolderExisted=true:isFolderExisted=false:isFolderExisted=false;
From SonarLint, if you already have the path, use path.toFile().exists() instead of Files.exists for better performance.
The Files.exists method has noticeably poor performance in JDK 8, and can slow an application significantly when used to check files that don't actually exist.
The same goes for Files.notExists, Files.isDirectory and Files.isRegularFile.
Noncompliant Code Example:
Path myPath;
if(java.nio.Files.exists(myPath)) { // Noncompliant
// do something
}
Compliant Solution:
Path myPath;
if(myPath.toFile().exists())) {
// do something
}

Categories

Resources