Java Box Grid - Receiving Question Marks Instead of a Grid [duplicate] - java

This question already has answers here:
Unicode in NetBeans 6.7.1
(1 answer)
Why Some Unicode Characters appears to be question mark in the console?
(3 answers)
Closed 16 days ago.
I am tasked with creating a box grid using Java with NetBeans v16 IDE. I have implemented the code however the grid is being displayed. I can provide the actual code I am using if its needed.
The program runs and I have validated the Unicode values are properly formatted and I am not using a code for a question mark.
private static final char WALL_TOP_BOTTOM = 0x2550;
private static final char WALL_LEFT_RIGHT = 0x2551;
private static final char WALL_TOP_LEFT_CORNER = 0x2554;
private static final char WALL_TOP_RIGHT_CORNER = 0x2557;
private static final char WALL_BOTTOM_RIGHT_CORNER = 0x255D;
private static final char WALL_BOTTOM_LEFT_CORNER = 0x255A;
private static final char BOX_CHAR = 0x2588;
private static final char EMPTY = 0x2591;
When running the program I receive:
-- exec-maven-plugin:3.0.0:exec (default-cli) # GridApp ---
????????????
????????????
????????????
????????????
????????????
????????????
????????????
????????????
????????????
????????????
????????????
????????????
Enter (U)p, (D)own, (L)eft, (R)ight, or (E)xit:

Related

How split over a string with a first and last index using java? [duplicate]

This question already has answers here:
Regular expression to extract text between square brackets
(15 answers)
Closed 4 years ago.
I want to split over a string (exemple : ABC-{9090}) with a first and last index using java
I want to get just the value between {} --> output : 9090
You can use below replaceAll for this purpose:
public class StringParsing {
public static void main(String[] args){
String s = "ABC-{9090}";
System.out.println(s.replaceAll("[^\\{]+\\{(.*?)\\}.*", "$1"));
}
}

Unable to increment a variable scanned in java [duplicate]

This question already has answers here:
concatenating string and numbers Java
(7 answers)
Closed 5 years ago.
Hello I'm a beginner in Java and i'm finding issuses to increment the variable age as it is red as a string or it is an integer
This is the Code :
public static void main(String[] args)
{
Scanner name= new Scanner(System.in);
System.out.println("Hello your name is "+name.nextLine());
Scanner in = new Scanner(System.in);
int age = in.nextInt();
System.out.println("In 17 September i will become "+age+1+" years old");
}
Whenever you add a String in a print statement, all further + signs are considered to be the concatenation operator, instead of the addition sign.
To fix, enclose it in brackets, like (age+1).

cast string to int java android [duplicate]

This question already has answers here:
How do I convert a String to an int in Java?
(47 answers)
Closed 6 years ago.
How can I convert a String to an int in Java?
My String contains only numbers and I want to return the number it represents.
For example, given the string "1234" the result should be the number 1234
String Availability = json.getString("Availability");before parsing value ="4"
int x = Integer.parseInt(Availability);here after parsing it gives me 2 i don't know why
You can use the foll function Integer.valueOf here is an example
public static void main(String args[]){
int num = Integer.valueOf("22");
num+=2;
System.out.println(num); // output 24
}

How to get an integer at a specified position in a string of integers? [duplicate]

This question already has answers here:
Java: parse int value from a char
(9 answers)
Closed 6 years ago.
If I have a string like String myString = "12345" and I want to return the value at index [0]. How do I do this? I've tried for example int foo = myString.charAt(0) and get a weird value like 49?
Use Character.getNumericValue():
String myString = "12345";
int foo = Character.getNumericValue(myString.charAt(0));

Default value of char is said to be '\u0000' but I got the output space character (' ') in java [duplicate]

This question already has an answer here:
Primitives/Objects Declaration, default initialization values
(1 answer)
Closed 7 years ago.
Here is the code I got the space output. I didn't figure out if '\u0000' means the space or something else.
`package com.string.test;
class CharTest {
char y;
public static void main(String args[]){
CharTest test = new CharTest();
System.out.println("Default value of char:----" + test.y + "----");
}
} `
A char has a default value of 'u0000'.
Reference this article: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Categories

Resources