Develop Reference

Parsing flat file with repeating section using regex

I have a flat file with data in following format:
1:00 PM
Name UniqueID
ABX 298819 12 519440AD3
12:00 AM
Name UniqueID
AX1 239949 01 119440AD3
Where each section starts with a time, followed by headers and then values. I am trying to capture each of these sections through regex, so I can get:
section 1:
1:00 PM
Name UniqueID
ABX 298819 12 519440AD3
section 2:
12:00 AM
Name UniqueID
AX1 239949 01 119440AD3
And later parse each of these sections in to java class object, which is given below:
public class Section {
String timestamp;
List<Row> rows;
}
public class Row {
String name;
String uniqueId;
}
but I am not able to extract the "text" between two positive regex matches. Below is the regular expression i tried:
((1[012]|[1-9]):[0-5][0-9](\\s)?(?i)(am|pm))(?=.*)
But it returns only the time values:
10:30 AM
1:00 PM
1:30 PM
10:30 AM
1:00 PM
1:30 PM
I even tried adding Pattern.MULTILINE to Pattern but it didn't work either.

Assuming the structure you showed us repeats throughout the file, then there are four types of lines in sequence: timestamp, header, data, empty line.
For example, if you want to separate the unique ID from the name, you could try:
String third = "ABX 298819 12 519440AD3";
String uniqueId = third.replaceAll(".*\\s+(\\w+)", "$1");
String name = third.replaceAll("(.*)\\s+\\w+", "$1");

Next digit after a word using index position in java

I am trying to solve this question:
Get document on some condition in elastic search java API
My logic is first we get all the position of months which is in string, After that i extract next word which is a 4 digit or 2 digit year, Then calculate difference using this.
For getting months position i am using this piece of code:-
String[] threeMonthArray=new String[]{" Jan "," Feb "," Mar "," Apr "," May "," June "," July "," Aug "," Sep "," Oct "," Nov "," Dec "};
String[] completeMonthArray=new String[]{"January","Feburary","March","April","May","June","July","Augest","September","October","November","December"};
List indexArray=new ArrayList();
for(int i=0;i<threeMonthArray.length;i++){
int index = parsedContent.toLowerCase().indexOf(threeMonthArray[i].toLowerCase());
while (index >= 0) {
System.out.println(threeMonthArray[i]+" : "+index+"------");
indexArray.add(index);
index = parsedContent.toLowerCase().indexOf(threeMonthArray[i].toLowerCase(), index + 1);
}
// System.out.println(threeMonthArray[i]+" : "+parsedContent.toLowerCase().indexOf(threeMonthArray[i].toLowerCase())+"------");
}
Collections.sort(indexArray);
System.out.println( indexArray);
And it's showing this output:-
[2873, 2884, 3086, 3098, 4303, 4315, 6251, 6262, 8130, 8142, 15700, 15711]
I am getting correct position. My problem is how i can get next word which must be a digit.
Jun 2010 to Sep 2011 First Document
Jun 2009 to Aug 2011 Second Document
Nov 2011 – Sep 2012 Third Document
Nov 2012- Sep 2013 Forth Document

You can use a regular expression to find the next number starting at the position of your last found month:
Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher(parsedContent);
if (m.find(index)) {
String year = m.group();
}

Regex: Get all words until a number of a special character is found

I am trying to extract movie names from a list that looks like this:
The Maze Runner 2014 DVDRip XviD MP3-RARBG
Fury 2014 DVDSCR x264 AC3-Blackjesus
Dracula's Untold Story (WebRip / 2014)
I need to extract the words up to the year or a special character like ( or [ but not '
The Maze Runner 2014 DVDRip XviD MP3-RARBG ==> The Maze Runner
Fury 2014 DVDSCR x264 AC3-Blackjesus ==> Fury
Dracula's Untold Story (WebRip / 2014) == Dracula's Untold Story
Dracula's Untold Story [WebRip / 2014] == Dracula's Untold Story
I have no idea how to go on about writing a complex regex like this. Any ideas?

The below code snippet can be helpful to meet your requirements
public static String extractMovieName(String movieNameString){
Pattern pattern = Pattern.compile("([\\w' ]+)([\\[]|[\\(]|[\\d]{4})");
Matcher matcher = pattern.matcher(movieNameString);
String extractedName = "";
if(matcher.find()){
extractedName = matcher.group(1);
}
return extractedName;
}

^[a-zA-Z0-9\ '-]+(?=\b\d{4}\b|\()
Try this.See demo.
http://regex101.com/r/yR3mM3/4

Try below code:
Example:
System.out.println("Fury 2014 DVDSCR x264 AC3-Blackjesus".replaceAll("\\s(\\d|\\(|\\[).*", ""));

splitting or tokenize comma with space and comma[JAVA]

January 22, 2014
I want to split the string into three but the second has , and space

If I understand you, you could use a single (zero or one matches) regular expression with something like -
String in = "January 22, 2014";
String[] arr = in.split(",?\\ ");
for (String str : arr) {
System.out.println(str);
}
Output is
January
22
2014

replace words using regex [duplicate]

This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
regex replace all ignore case
I need to replace all occurrences of Sony Ericsson with a tilda in between them. This is what I have tried
String outText="";
String inText="Sony Ericsson is a leading company in mobile. The company sony ericsson was found in oct 2001";
String word = "sony ericsson";
outText = inText.replaceAll(word, word.replaceAll(" ", "~"));
System.out.println(outText);
The output of this is
Sony Ericsson is a leading company in mobile. The company sony~ericsson was found in oct 2001
But what I want is
Sony~Ericsson is a leading company in mobile. The company sony~ericsson was found in oct 2001
It should ignore cases & give the desired output.

Change it to
outText = inText.replaceAll("(?i)" + word, word.replaceAll(" ", "~"));
to make the search / replace case insensitive.
String outText="";
String inText="Sony Ericsson is a leading company in mobile. " +
"The company sony ericsson was found in oct 2001";
String word = "sony ericsson";
outText = inText.replaceAll("(?i)" + word, word.replaceAll(" ", "~"));
System.out.println(outText);
Output:
sony~ericsson is a leading company in mobile.
The company sony~ericsson was found in oct 2001
Avoid ruining the original capitalization:
In the above approach however, you're ruining the capitalization of the replaced word. Here is a better suggestion:
String inText="Sony Ericsson is a leading company in mobile. " +
"The company sony ericsson was found in oct 2001";
String word = "sony ericsson";
Pattern p = Pattern.compile(word, Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(inText);
StringBuffer sb = new StringBuffer();
while (m.find()) {
String replacement = m.group().replace(' ', '~');
m.appendReplacement(sb, Matcher.quoteReplacement(replacement));
}
m.appendTail(sb);
String outText = sb.toString();
System.out.println(outText);
Output:
Sony~Ericsson is a leading company in mobile.
The company sony~ericsson was found in oct 2001

str.replaceAll(regex, repl) is equal to Pattern.compile(regex).matcher(str).replaceAll(repl). Thus, you can make your matcher case-insensitive with a flag:
Pattern.compile(regex, Pattern.CASE_INSENSITIVE).matcher(str).replaceAll(repl)
Using backreferences to preserve case:
Pattern.compile("(sony) (ericsson)", Pattern.CASE_INSENSITIVE)
.matcher(str)
.replaceAll("$1~$2")
Gives:
Sony~Ericsson is a leading company in mobile. The company sony~ericsson was found in oct 2001

String outText = inText.replaceAll("(?i)(Sony) (Ericsson)", "$1~$2");
Output:
Sony~Ericsson is a leading company in mobile. The company Sony~ericsson was found in oct 2001