Some comparison between Java package and C# namespace - java

From Programming Language Pragmatics 4ed by Michael Scott
C# follows Java’s lead in extracting header information automatically
from complete class definitions.
Then it continues to mention where namespaces in C# differ from packages in Java:
Its module-level syntax, however, is based
on the namespaces of C++, which allow a single file to contain
fragments of multiple namespaces.
Does Java allow a single file to contain fragments of multiple
packages?
There is also no notion of standard search
path in C#: to build a complete program, the programmer must provide
the compiler with a complete list of all the files required.
How does a C# programmer provide the compiler with a complete
list of all the files required?
Thanks.

Does Java allow a single file to contain fragments of multiple packages?
If there is a package statement, it must be the first line of your Java source code. This means that the answer to your question is "no": you can have at most one package declaration per Java source file.
How does a C# programmer must provide the compiler with a complete list of all the files required?
This applies only to building on the command line, because IDEs take care of this automatically. When you build your code on the command line with csc.exe you must provide a list of all files composing your module either by listing them one-by-one, e.g.
csc src\File1.cs src\File2.cs src\File3.cs
or by specifying a pattern:
csc src\*.cs

Related

Are there any Java Class Library "header files" containing all method descriptors in the standard library?

In order to create a valid .class file, every method has to have a full internal name and type descriptors associated with it. When procedurally creating these, is there some sort of lookup table one can use (outside of Java, where a ClassLoader can be used) to get these type descriptors from a method name? For example, how would one go from Scanner.hasNextByte to boolean java.util.Scanner.hasNextByte(int) / boolean java.util.Scanner.hasNextByte() (or even from java.util.Scanner.hasNextByte to boolean java.util.Scanner.hasNextByte(int) / boolean java.util.Scanner.hasNextByte())? The above example has overloading in it, which is another problem a human- but mostly computer-readable declarations file would hopefully address.
I've found many sources of human-readable documentation like https://docs.oracle.com/javase/8/docs/api/index.html containing uses of each method, hyperlinks to other places, etc. but never a simple text file or collection of files containing just declarations in any format. If there's no such file(s) don't worry about it, I can try and scrape some annoying HTML files, but if there is it would save a lot of time. Thanks!
The short answer is No.
There isn't a "header file" containing the class and method signatures for the Java class libraries. The Java tool chain has no need for such a thing. Nor do 3rd-party Java compilers, or compilers for other languages that rely on the Java SE class libraries.
AFAIK, there isn't a 3rd-party tool that builds such a file or an equivalent database or in-memory data structures.
You could create one though.
You could chose an existing Java parsing library, and use it to build parse trees for all of the source files in the class library, and emit the information that you need.
You could potentially create a custom Javadoc "doclet" plugin to emit the information.
Having said that, I don't understand why you would need such a mapping. Surely, your IDE does this already ... and exposes the information via some internal API. And if this is not for an IDE plugin, what it is for?
You commented:
I'm making a compiler for a JVM-based programming language ....
Ah ... so your compiler should do what other compilers do. Get the information from the ".class" file. You can either load the class using a standard or custom class loader, or you can use a library like asm or bcel or javassist ... which can read a ".class" file without loading it.
(I haven't checked, but I think the standard javac compiler uses an internal API to do this.)
Note that your proposed approaches won't work for interfacing with 3rd-party Java libraries where the source code is not available and/or the javadoc is not scrapable.
What about building it from the source files for the standard library?
The Oracle Java 8 API web pages you referenced was created by Javadoc processing of source files for the Java standard library.
If you use an IDE with a debugger, there is a good chance you already have much of the standard library source code downloaded. After all, if you set a break point, and then follow the program step-by-step with "Step into", you can trace the execution of the program into standard library methods. The source files would be part of the JDK.
However, some parts of the standard library source might not be available, due to licensing restrictions.

"Mechanically generated" java source files in the Java source code

As I was looking through the Java source code, I found some unusual files, mostly related to ByteBuffers in the java.nio package which had a very messy source code and were labelled This file was mechanically generated: Do not edit!.
These files also contained large portions of blank lines (some even in the middle of javadocs (!!?)), presumably to prevent the line numbers from changing. I have also seen a few java decompilers, such as procyon-decompiler, which have an option to keep line numbers, but I doubt that's the case, because putting blank lines before the final accolade changes nothing.
Here are a few of these files (I couldn't find any links to them online and didn't pastebin them because I don't want to break any copyright, but you can find them in the src.zip folder at the root of your JDK installation folder):
java.nio.ByteBuffer
java.nio.DirectByteBufferR
java.nio.Bits
java.nio.BufferOverflowException
I'd be curious to know:
Which tool generated these files?
Why does the tool keep the line numbers the same? Is it to make debugging (stacktraces) easier?
Why would a tool be used to generate them, while all other classes are programmed by humans?
Why would the tool put blank lines randomly inside parentheses, before the final accolade, or even in javadocs?
I can probably not answer all of the questions, but some background is:
In the Makefile at http://hg.openjdk.java.net/jdk7/jdk7/jdk/file/9b8c96f96a0f/make/java/nio/Makefile, they are generating different java source files from the same template file through some preprocessor:
...
$(BUF_GEN)/CharBuffer.java: $(X_BUF_TEMPLATE) $(GEN_BUFFER_SH)
$(prep-target)
#$(RM) $#.temp
TYPE=char SRC=$< DST=$#.temp $(GEN_BUFFER_CMD)
$(MV) $#.temp $#
$(BUF_GEN)/ShortBuffer.java: $(X_BUF_TEMPLATE) $(GEN_BUFFER_SH)
$(prep-target)
#$(RM) $#.temp
TYPE=short SRC=$< DST=$#.temp $(GEN_BUFFER_CMD)
$(MV) $#.temp $#
...
$(X_BUF_TEMPLATE) refers to X-Buffer.java.template, which is the source for typed buffers like CharBuffer, ShortBuffer and some more.
Note: The URLs might change in the future. Also sorry for referring to Java 7 - in Java 8 they have modified the build system, I did not find the corresponding Makefiles so far.
Which tool generated these files?
GEN_BUFFER_SH / GEN_BUFFER_CMD finally refers to genBuffer.sh, so the script which creates these files is http://hg.openjdk.java.net/jdk7/jdk7/jdk/file/9b8c96f96a0f/make/java/nio/genBuffer.sh.
Why would a tool be used to generate them, while all other classes are programmed by humans?
I don't have an authoritative answer for this specific case, but usually you are using code generation tools
if you need to create a lot of similar classes/methods which only differ in some detail, but which is subtle enough so that you can not use established mechanisms like generics or method parameters (probably the case here, since the buffers are generated for primitive types which can not be used with Generics)
if you need to create complex algorithms from a much simpler representation (like generating parsers from a grammar).
Why does the tool keep the line numbers the same? Is it to make debugging (stacktraces) easier?
I am guessing: yes, its to retain the line numbers in stack traces so that they match the template files. Other tools like the C preprocessor work similar.

How to break up an Android activity in multiple files

In Android, a lot of functionality is in the Activity derived class. When an activity gets big (with many event handlers and such), the Java file can get large and very cluttered.
Is there a way to "break up" a Java class code file, like C# has the partial keyword?
As others have pointed out, you cannot split the actual file (I view this as a good thing).
You can extract view related functionality in custom views and fragments. Everything else (business logic, Web service access, DB access, etc.) can be in 'helper' classes you use in your activity. Even though activities are the God objects in Android, you don't have to write everything inside the actual activity class. It should only coordinate stuff and implement necessary callbacks and event handlers (which technically can be in their own classes as well).
short answer ? no.
quoted from wikipedia
The Sun Microsystems Java compiler requires that a source file name must match the only public class inside it, while C# allows multiple public classes in the same file, and puts no restrictions on the file name. C# 2.0 and later allows splitting a class definition into several files by using the partial keyword in the source code. In Java, a public class will always be in its own source file. In C#, source code files and logical units separation are not tightly related.
so while you may rework your design and relegate some code to utility classes to unclutter the code, you can not seperate the code of a single class across two files in java.
No. Java source codes can not be split across multiple files.
From the http://en.wikipedia.org/wiki/Comparison_of_Java_and_C_Sharp
The Sun Microsystems Java compiler requires that a source file name must match the only public class inside it, while C# allows multiple public classes in the same file, and puts no restrictions on the file name. C# 2.0 and later allows a class definition to be split into several files, by using the partial keyword in the source code. In Java, a public class will always be in its own source file. In C#, source code files and logical units separation are not tightly related.

Why does Java generate Multiple .class files on compilation?

In Java, on compilation we get a .class file for each class( including nested classes and interfaces) defined in the source file.What is the reason for this multiple .class file generation? Is it for simplifying the reusablity of the class? Why not generate one .class for one .java file?
The JVM needs to be able to find the code for a given class, given its name. If there's potentially no relationship between the source filename and the code filename, and you want the code filename to be based on the source filename, how would you expect it to load the code?
As an example: suppose I were to compile Foo.java which contains class Bar.
Another class then refers to Bar, so the JVM needs the code for it... how would you suggest it finds the file?
Note that in .NET there's a separate of unit of deployment called the assembly - and a reference to a type includes the assembly name as well, but that's slightly different from what you were proposing.
In response to #Jon Skeet's rhetorical question:
Another class then refers to Bar, so the JVM needs the code for it... how would you suggest it finds the file?
Suppose (hypothetically) that the Java classfile format represented nested / inner classes by embedding them in the classfile for the outermost class. The binary name for the Bar is "Lsome/pkg/Foo$Bar;". The class loader could split the name at the "$" character, use the first part to locate the classfile for Foo, and then navigate to the embedded Bar class representation.
I think that the real reason that inner/nested classes have separate classfiles is historical. IIRC, Java 1.0 did not support nested or inner classes, and hence the corresponding classfile formats did not need to deal with them. When Java 1.1 was created (supporting inner/nested classes), Sun wanted the classfile format to be compatible with the classfiles produced by the Java 1.0 compiler. So they chose to implement inner / nested classes as separate classfiles, using the reserved "$" character in the binary classname.
A second possible reason is that the flat format simplifies class loading compared to a hypothetical embedded format.
And finally, there was (and still is) no compelling reason for them NOT to use a flat file format. It maybe creates some minor head-scratching when some programmer wants to load inner classes using Class.forName() but that is pretty rare occurrence ... and the solution is straight-forward.
That's is a design decision regarding a compilation unit, made by the developers.
Compiled classes are usually combined in a jar file.
Extract from Java Language Spec
7.3 Compilation Units
CompilationUnit is the goal symbol (§2.1) for the syntactic grammar (§2.3) of
Java programs.
Types declared in different compilation units can depend on each other, circularly.
A Java compiler must arrange to compile all such types at the same time.

Why is each public class in a separate file?

I recently started learning Java and found it very strange that every Java public class must be declared in a separate file. I am a C# programmer and C# doesn't enforce any such restriction.
Why does Java do this? Were there any design considerations?
Edit (based on a few answers):
Why is Java not removing this restriction now in the age of IDEs? This will not break any existing code (or will it?).
I have just taken a C# solution and did just this (remove any file that had multiple public classes in them) and broke them out to individual files and this has made life much easier.
If you have multiple public classes in a file you have a few issues:
What do you name the file? One of the public classes? Another name? People have enough issues around poor solution code organization and file naming conventions to have one extra issue.
Also, when you are browsing the file / project explorer its good that things aren't hidden. For example you see one file and drill down and there are 200 classes all mushed together. If you have one file one class, you can organize your tests better and get a feel for the structure and complexity of a solution.
I think Java got this right.
According to the Java Language Specification, Third Edition:
This restriction implies that there must be at most one such type per compilation unit. This restriction makes it easy for a compiler for the Java programming language or an implementation of the Java virtual machine to find a named class within a package; for example, the source code for a public type wet.sprocket.Toad would be found in a file Toad.java in the directory wet/sprocket, and the corresponding object code would be found in the file Toad.class in the same directory.
Emphasis is mine.
It seems like basically they wanted to translate the OS's directory separator into dots for namespaces, and vice versa.
So yes, it was a design consideration of some sort.
From Thinking in Java
:
There can be only one public class per compilation unit (file).
The idea is that each compilation unit has a single public interface represented by that public class. It can have as many supporting “friendly” classes as you want. If you have more than one public class inside a compilation unit, the compiler will give you an error message.
From the specification (7.2.6)
When packages are stored in a file system (?7.2.1), the host system may choose to enforce the restriction that it is a compile-time error if a type is not found in a file under a name composed of the type name plus an extension (such as .java or .jav) if either of the following is true:
The type is referred to by code in other compilation units of the package in which the type is declared.
The type is declared public (and therefore is potentially accessible from code in other packages).
This restriction implies that there must be at most one such type per compilation unit.
This restriction makes it easy for a compiler for the Java programming language or an implementation of the Java virtual machine to find a named class within a package; for example, the source code for a public type wet.sprocket.Toad would be found in a file Toad.java in the directory wet/sprocket, and the corresponding object code would be found in the file Toad.class in the same directory.
In short: it may be about finding classes without having to load everything on your classpath.
Edit: "may choose" seems like it leaves the possibility to not follow that restriction, and the meaning of "may" is probable the one described in RFC 2119 (i.e. "optional")
In practice though, this is enforced in so many platform and relied upon by so many tools and IDE that I do not see any "host system" choosing to not enforce that restriction.
From "Once upon an Oak ..."
It's pretty obvious - like most things are once you know the design reasons - the compiler would have to make an additional pass through all the compilation units (.java files) to figure out what classes were where, and that would make the compilation even slower.
(Note:
the Oak Language Specification for Oak version 0.2 (postcript document): Oak was the original name of what is now commonly known as Java, and this manual is the oldest manual available for Oak (i.e. Java).
For more history on the origins of Java, please have a look at the Green Project and Java(TM) Technology: An Early History
)
It's just to avoid confusion in the sense that Java was created with simplicity in mind from the perspective of the developer. Your "primary" classes are your public classes and they are easy to find (by a human) if they are in a file with the same name and in a directory specified by the class's package.
You must recall that the Java language was developed in the mid-90s, in the days before IDEs made code navigation and searching a breeze.
If a class is only used by one other class, make it a private inner class. This way you have your multiple classes in a file.
If a class is used by multiple other classes, which of these classes would you put into the same file? All three? You would end up having all your classes in a single file...
That's just how the language designers decided to do it. I think the main reason was to optimize the compiler pass-throughs - the compiler does not have to guess or parse through files to locate the public classes. I think it's actually a good thing, it makes the code files much easier to find, and forces you to stay away from putting too much into one file. I also like how Java forces you to put your code files in the same directory structure as the package - that makes it easy to locate any code file.
It is technically legal to have multiple Java top level classes in one file. However this is considered to be bad practice (in most cases), and some Java tools may not work if you do this.
The JLS says this:
When packages are stored in a file
system (§7.2.1), the host system may
choose to enforce the restriction that
it is a compile-time error if a type
is not found in a file under a name
composed of the type name plus an
extension (such as .java or .jav) if
either of the following is true:
The type is referred to by code in other compilation units of the package in which the type is declared.
The type is declared public (and therefore is potentially accessible from code in other packages).
Note the use of may in the JLS text. This says that a compiler may reject this as invalid, or it may not. That is not a good situation if you are trying to build your Java code to be portable at the source code level. Thus, even if multiple classes in one source file works on your development platform, it is bad practice to do this.
My understanding is that this "permission to reject" is a design decision that is intended in part to make it easier to implement Java on a wider range of platforms. If (conversely) the JLS required all compilers to support source files containing multiple classes, there would be conceptual issues implementing Java on a platform which wasn't file-system based.
In practice, seasoned Java developers don't miss being able to do this at all. Modularization and information hiding are better done using an appropriate combination of packages, class access modifiers and inner or nested classes.
Why is java not removing this restriction now in the age of IDEs? This will not break any existing code (or will it?).
Now all code is uniform. When you see a source file you know what to expect. it is same for every project. If java were to remove this convention you have to relearn code structure for every project you work on, where as now you learn it once and apply it everywhere. We should not be trusting IDE's for everything.
Not really an answer to the question but a data point none the less.
I grepped the headers of my personal C++ utilty library (you can get it yourself from here) and almost all of the header files that actually do declare classes (some just declare free functions) declare more than one class. I like to think of myself as a pretty good C++ designer (though the library is a bit of a bodge in places - I'm its only user), so I suggest that for C++ at least, multiple classes in the same file are normal and even good practice.
It allows for simpler heuristics for going from Foobar.class to Foobar.java.
If Foobar could be in any Java file you have a mapping problem, which may eventually mean you have to do a full scan of all java files to locate the definition of the class.
Personally I have found this to be one of the strange rules that combined result in that Java applications can grow very large and still be sturdy.
Well, actually it is an optional restriction according to Java Language Specification (Section 7.6, Page No. 209) but followed by Oracle Java compiler as a mandatory restriction. According to Java Language Specification,
When packages are stored in a file system (§7.2.1), the host system
may choose to enforce the restriction that it is a compile-time error
if a type is not found in a file under a name composed of the type
name plus an extension (such as .java or .jav) if either of the
following is true:
The type is referred to by code in other compilation units of the package in which the type is declared.
The type is declared public (and therefore is potentially accessible from code in other packages).
This restriction implies that there must be at most one such type per
compilation unit. This restriction makes it easy for a Java compiler
to find a named class within a package.
In practice, many programmers choose to put each class or interface
type in its own compilation unit, whether or not it is public or is
referred to by code in other compilation units.
For example, the source code for a public type wet.sprocket.Toad would
be found in a file Toad.java in the directory wet/sprocket , and the
corresponding object code would be found in the file Toad.class in the
same directory.
To get more clear picture let's imagine there are two public classes public class A and public class B in a same source file and A class have reference to the not yet compiled class B. And we are compiling (compiling-linking-loading) class A now while linking to class B compiler will be forced to examine each *.java files within the current package because class B don’t have it’s specific B.java file. So In above case, it is a little bit time consuming for the compiler to find which class lies under which source file and in which class the main method lies.
So the reason behind keeping one public class per source file is to actually make compilation process faster because it enables a more efficient lookup of the source and compiled files during linking (import statements). The idea is if you know the name of a class, you know where it should be found for each classpath entry and no indexing will be required.
And also as soon as we execute our application JVM by default looks for the public class (since no restrictions and can be accessible from anywhere) and also looks for public static void main(String args[]) in that public class. Public class acts as the initial class from where the JVM instance for the Java application (program) is begun. So when we provide more than one public class in a program the compiler itself stops you by throwing an error. This is because later we can’t confuse the JVM as to which class to be its initial class because only one public class with the public static void main(String args[]) is the initial class for JVM.
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