Develop Reference

Read specific line out of String

I have a String that looks like this:
String meta = "1 \n"
+ "Herst \n"
+ "01 Jan 2019 – 31 Dec 2020 \n"
+ "01 Jan 2020 \n"
+ "CONFIG \n"
+ "XML \n"
+ "AES \n"
+ "RSA \n"
+ "256 \n"
+ "16 \n"
+ "128 \n";
What is the smartest way if I want to read a specific line out of this String in Java?
For example, I need in another part of my code the number of the second last line (in this case it's 16). How can I read this number out of the String?

If it's already in String form, just split it into lines using \n as a delimiter to get an array of lines:
String[] lines = meta.split("\n");
Then you can easily get a specific line. For instance, System.out.println(lines[9]) will print 16.
If you need the 16 in the form of an int, you'd need to remove the whitespaces around it, and parse it:
int parsed = Integer.parseInt(lines[9].trim());

What Regular Expression Will Get Last Price Listed On Receipt?

I have the following expression:
(?!\d+\s+TOTAL\s+)\$+\d+\.?\d+\s+
It produces the result "$23.00$0.03$23.80" from the following text:
SPEEDWAY 3007906
Wallace NC 28466
TRAM: 1086244
9/17/2017 2:12 pm
Pump 08
Regular Unleaded
8,716 # $2,639/6131
GAS TOTAL $23.00
TAX $0.03
TOTAL $23.80
Uisa
What regular expression will pull just $23.80 in this case? If I add positive lookahead, so that the expression is "(?!\d+\s+TOTAL\s+)\$+\d+\.?\d+\s+(?=.*\$\d+\.?\d+)", the result is "$23.00$0.03" and not "$23.80".
Please help. Thanks in advance.

Try this:
(?<=^TOTAL)\s*(\$\s*\d+\.?\d*)\s*$
Make sure you use MULTILINE match.
This will match all the spaces around the value, so you may want to strip those out to get the value
Example:
String in = "SPEEDWAY 3007906\n" +
"Wallace NC 28466 \n" +
"TRAM: 1086244 \n" +
"9/17/2017 2:12 pm \n" +
"Pump 08 \n" +
"Regular Unleaded \n" +
"8,716 # $2,639/6131 \n" +
"GAS TOTAL $23.00\n" +
"TAX $0.03 \n" +
"TOTAL $23.80\n" +
"Uisa ";
Pattern p = Pattern.compile("(?<=^TOTAL)\\s*(\\$\\s*\\d+\\.?\\d*)\\s*$", MULTILINE);
Matcher m = p.matcher(in);
if(m.find()) {
System.out.println(m.group(1));
}
This should print just the matched value

Maybe you could use a negative lookbehind to assert that what is before TOTAL is not GAS and capture your value in group 1.
(?<!GAS )TOTAL\s*(\$\d+\.\d+)
Demo output Java

Parse and print only the stack trace when Regex pattern matches

I want to print just the stack trace starting from and at cab.ces.upgrade.controller.UpgradeRecommendationController.getPackageOffers(UpgradeRecommendationController.java:1234). This is how I get output.
**** Error Wed Jul 05 23:23:49 GMT 2017 1499297029577 /lll/dynamo/servlet/pipeline/RequestScopeManager/RequestScope-23596/cab/ces/upgrade/manager/business/UpgradeRecommendationsBusinessManager at cab.ces.upgrade.controller.UpgradeRecommendationController.getPackageOffers(UpgradeRecommendationController.java:1234)
So I need to remove **** Error Wed Jul 05 23:23:49 GMT 2017 1499297029577 /lll/dynamo/servlet/pipeline/RequestScopeManager/RequestScope-23596/cab/ces/upgrade/manager/business/UpgradeRecommendationsBusinessManager
My Code
if((strLine.contains("**** Error") )){
//|| (strLine.contains("(CreditCheckManager")
//String sPattern = "\\tat (.*)\\.(.*)\\(([^:]*):?([\\d]*)\\)";
Matcher m = p.matcher(strLine);
if(m.find()){
totCount++;
iCount++;
if((iCount==1) ){
System.out.println("Class name:- " + m.group(3));
System.out.println("Line Number:- " + m.group(4));
System.out.println();
System.out.println("VodafoneSystemException occurence count: " + exCount);
System.out.println();
System.out.println("VodafoneSystemException stack trace count: " + totCount);
}
System.out.println(strLine);

Use at (.)+ to find all string after at, See regex

Why is this query not returning the data( in XQuery, Java)?

This is for XQuery used in Java. My code is working with other XML files, but this time it is not returning the required data. The faulty code is below. What is wrong with it? Thanks.
String queryString =
"declare variable $docName as xs:string external;" + sep +
" for $TRACK in doc($docName)/playlist/tracklist/track " +
" return " +
" <track><title>{$TRACK/title/text()}</title>" +
" <location>{$TRACK/location/text()}</location></track>";
This is the target XML:
<?xml version="1.0"?>
-<playlist xmlns="http://xspf.org/ns/0/" version="1">
-<trackList>-<track><location>http://radiotool.com/242.mp3</location><title>New York</title></track>
-<track><location>http://radiotool.com/243.mp3</location> <title>Chicago Repeater</title></track>
</trackList></playlist>

It's probably because the source XML uses a namespace and your XPath doesn't. How about this:
String queryString =
"declare namespace xsp='http://xspf.org/ns/0/'; " +
"declare variable $docName as xs:string external;" + sep +
" for $TRACK in doc($docName)/xsp:playlist/xsp:trackList/xsp:track " +
" return " +
" <track><title>{$TRACK/xsp:title/text()}</title>" +
" <location>{$TRACK/xsp:location/text()}</location></track>";

Java - Regex for the given string

I have the following html code segment:
<br>
Date: 2010-06-20, 1:37AM PDT<br>
<br>
Daddy: www.google.com
<br>
I want to extract
Date: 2010-06-20, 1:37AM PDT
and
Daddy: www.google.com
with the help of java regex.
So what regex I should use?

This should give you a nice starting point:
String text =
" <br>\n" +
" Date: 2010-06-20, 1:37AM PDT<br> \n" +
" <br> \n" +
"Daddy: www.google.com \n" +
"<br>";
String[] parts = text.split("(?:\\s*<br>\\s*)+");
for (String part : parts) {
System.out.println("[" + part + "]");
}
This prints (as seen on ideone.com):
[]
[Date: 2010-06-20, 1:37AM PDT]
[Daddy: www.google.com]
This uses String[] String.split(String regex). The regex pattern is "one or more of <br>, with preceding or trailing whitespaces.
Guava alternative
You can also use Splitter from Guava. It's actually a lot more readable, and can omitEmptyStrings().
Splitter splitter = Splitter.on("<br>").trimResults().omitEmptyStrings();
for (String part : splitter.split(text)) {
System.out.println("[" + part + "]");
}
This prints:
[Date: 2010-06-20, 1:37AM PDT]
[Daddy: www.google.com]
Related questions
String split array